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2 years ago

9

Julie and her brother go to Atlanta to ride the Sky View Ferris wheel. It measures 200 feet in diameter. I want to know the dist

ance around the Ferris Wheel. Would I use Circumference or Area? B)What is the formula needed to solve this problem? C)What is the distance traveled in one rotation? Explain how you used the formula to solve the problem. need help

1 answer:

Zinaida [17]2 years ago

8 0

Answer:

a) Circumference of Ferris wheel.

b) $\text{Circumference} = \pi d$

c) 628 feet

Step-by-step explanation:

We are given the following in question:

Diameter of Ferris Wheel = 200 feet

a) Distance around Ferris wheel

The distance around Ferris wheel is given by the circumference of Ferris wheel.

b) Formula to calculate circumference

$\text{Circumference} = \pi d$

where d is the diameter of he wheel.

c) Distance traveled in one rotation

This will be given by the circumference of the Ferris wheel.

$\text{Distance} = \pi d = 3.14\times 200 = 628\text{ feet}$

Thus, the distance traveled in one rotation is 628 feet.

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Answer:

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Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

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= 0 $36^{o}$

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$84^{o}$ + <S = $180^{o}$

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Applying the Sine rule,

$\frac{y}{Sin P}$ = $\frac{x}{Sin Q}$ = $\frac{z}{Sin S}$

$\frac{y}{Sin P}$ = $\frac{z}{Sin S}$

$\frac{y}{Sin 48^{o} }$ = $\frac{17}{Sin 96^{o} }$

$\frac{y}{0.74314}$ = $\frac{17}{0.99452}$

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= 12.703

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$\frac{x}{Sin Q}$ = $\frac{z}{Sin S}$

$\frac{x}{Sin 36^{o} }$ = $\frac{17}{Sin 96^{o} }$

$\frac{x}{0.58779}$ = $\frac{17}{0.99452}$

⇒ x = $\frac{9.992430}{0.99452}$

= 10.0475

x = 10.05 km

Thus,

the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

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