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Mumz [18]
3 years ago
9

Julie and her brother go to Atlanta to ride the Sky View Ferris wheel. It measures 200 feet in diameter. I want to know the dist

ance around the Ferris Wheel. Would I use Circumference or Area? B)What is the formula needed to solve this problem? C)What is the distance traveled in one rotation? Explain how you used the formula to solve the problem. need help
Mathematics
1 answer:
Zinaida [17]3 years ago
8 0

Answer:

a) Circumference of Ferris wheel.

b) \text{Circumference} = \pi d

c) 628 feet

Step-by-step explanation:

We are given the following in question:

Diameter of Ferris Wheel = 200 feet

a) Distance around Ferris wheel

The distance around Ferris wheel is given by the circumference of Ferris wheel.

b) Formula to calculate circumference

\text{Circumference} = \pi d

where d is the diameter of he wheel.

c) Distance traveled in one rotation

This will be given by the circumference of the Ferris wheel.

\text{Distance} = \pi d = 3.14\times 200 = 628\text{ feet}

Thus, the distance traveled in one rotation is 628 feet.

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Step-by-step explanation:

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Marty has a driveway that is 200 feet long. The tires on her car have a diameter of 18 inches. What is the fewest number of tire
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Step-by-step explanation:

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First, measure the diameter of the tire in inches.

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3 0
2 years ago
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write the equation in slope-intercept form of the line passing through the points (-3, -2) and (-5, 2) hint: y = mx + b, all wor
Mama L [17]

Answer:

y(x) = -2x -8

Step-by-step explanation:

using the hint, insert the points (x,y) in the equation:

-2 = -3m + b       eq1

2 = -5m + b        eq2

eq2 - eq1 :  

4 = -2m  ==> m = -2

insert m in eq1:    

-2 = -3*(-2) +b   ==> b = -8

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3 years ago
Mr.Addison is building a sandbox shaped like a rectangular prism.The sandbox is 8 feet long,6 feet wide,and 1.5 feet deep.How ma
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7 0
3 years ago
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95 POINTS! PLEASE HELP!
aliina [53]

Answer:

1. 3

2. 2

3. 2

4. 6

5. No solution

Step-by-step explanation:

2x+3y=8 (1)

-6x+4y=11 (2)

3(1) + (2)

6x + 9y = 24

-6x + 4y = 11

13y = 35

y = 35/13

x = -1/26

3x-y=3 (1)

-2x+2y=6 (2)

2(1) + (2)

6x - 2y = 6

-2x + 2y = 6

4x = 12

x = 3

y = 3(3) - 3 = 6

3x+4y=-10 (1)

5x-2y=18 (2)

(1) + 2(2)

3x + 4y = -10

10x - 4y = 36

13x = 26

x = 2

5x-2y=3 (1)

2x-y=0 (2)

(1) - 2(2)

5x - 2y = 3

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x = 3

2(3) - y = 0

y = 6

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6x+4y=14 (2)

2(1) - (2)

6x + 4y = 20

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0 = 6 is a false statement so no solution

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3 years ago
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