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zimovet [89]
3 years ago
6

Consider the Polynomial P(x)=x^3-5x^2-x+5. is (x-5) a factor?

Mathematics
1 answer:
Alborosie3 years ago
8 0

Answer:

Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)

Step-by-step explanation:

<u>Step 1:  Factor</u>

p(x) = x^3 - 5x^2 - x + 5

<em>p(x) = (x - 5)(x + 1)(x - 1)</em>

<em />

<em>Yes, the remainder is 0 so, x-5 is a factor of p(x)</em>

<em />

Answer:  Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)

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Question : 1

weight of microbe in a test tube is 0.001 g,

weight of 456 such test tubes :

  • 456 \times 0.001

  • 456 \times  \dfrac{1}{1000}

  • \dfrac{456}{1000}

  • 0.456

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  • 456 g

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One crate weights 32.5 kg

the, 100 crates weight :

  • 32.5 \times 100

  • 3250 \: kg

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3. Push ups in one day - 53

push ups in 10 days :

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1 metal ball weights 5727 kg,

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3 years ago
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If you and 4 go to buy a drone and you find that it will cost you each $30. How many friends would you need to have with you if
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Find an equation of the line tangent to the curve √xy + 4y = 39 at the point (1,9)?
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sqrt(xy) + 4 dy/dx = 39

0.5(xy)^(-0.5) * (y + x dy/dx) + 4dy/dx=  0

No need to amplify simply plug in the given point ( 1,9)

0.5 ( 1 * 9)^(-0.5)* ( 9 + dy/dx) + 4dy/dx  = 0 

Solve for dy/dx

1/6( 9  + dy/dx)  = -4dy/dx

9 + dy/dx = -24 dy/dx

-25dy/dx = 9

dy/dx = -9/25

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