Answer:
Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)
Step-by-step explanation:
<u>Step 1: Factor</u>
p(x) = x^3 - 5x^2 - x + 5
<em>p(x) = (x - 5)(x + 1)(x - 1)</em>
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<em>Yes, the remainder is 0 so, x-5 is a factor of p(x)</em>
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Answer: Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)