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3 years ago

Whoever answers this gets brainliest plsss help

Mathematics

1 answer:

Karolina [17]3 years ago

7 0

hope it helped. I have solved in the same paper. plz don't mind.

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3x-4=13 solve inequality plz show work !

dimulka [17.4K]

3x-4=13
First you want all your x's on one side, and all your ordinary numbers on the other.
Add four to both sides to get rid of the "-4" part on the left.
Your new equation is 3x = 17
Divide each side by 3 to find X.
x= 17/3 or 5 2/3

7 0

3 years ago

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1 Pound brown sugar is equivalent to _____ cups

iogann1982 [59]

Answer:

3 1/2 or said as 3.5 cups is equal to 1 pound

Step-by-step explanation:

1 Pound brown sugar is equivalent to ___3 1/2 or 3.5 __ cups

Hope This Helped

7 0

1 year ago

Brad wants to buy flowers for

Elis [28]

He wants to buy flowers for me lol

3 0

3 years ago

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

2 years ago

The midpoint of a line segment is the point halfway between its endpoints.<br><br> True or False?

horrorfan [7]

This is true. You can remember by it saying mid, as in middle.

5 0

3 years ago

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