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stiv31 [10]
3 years ago
6

NEED HELP ASAP

Mathematics
2 answers:
nikdorinn [45]3 years ago
8 0

The second way you can do it is rotate 180 degrees around point C , dilate ,then translate 3 units up and 2 units to the left

spin [16.1K]3 years ago
7 0

Answer:

a) The figures are not congruent, but similar. This tells me in order to transform one of the figures, I need to condense the shape and flip it over both horizontally and vertically in order for it to be identical.

b) condensing the figure, flipping horizontally, flipping vertically

c) sorry, not able to think of a second sequence off the top of my head.

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A bag contains 8 black beads and 4 white beads. If 2 beads are drawn at random, what is the probability that both beads are blac
maria [59]

Answer:

14/33

Step-by-step explanation:

The total amount of beads is 8+4 = 12.  8 of these are black beads, so that is what we want, so 8/12 or 2/3.  For the second one, one black bead is already taken so 8-1 = 7 are left and for the total 12 - 1 = 11 are left, so 7/11.  Multiply this by 2/3 and we get 14/33.

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3 years ago
Riley called for pizza delivery. She was told the cost is $5 per pizza plus a $6 delivery charge. Fill in the blanks to create a
Nimfa-mama [501]

Answer:

subtract the delivery fee from the 20 dollars. $20 - $6 = $14. 2. Find the number of pizzas with the $14 that she can use. $14 ÷ $5 = 2 R $4.

Step-by-step explanation:

6 0
2 years ago
It costs $23.50 to enter an amusement park and $0.25 to ride a ride. You have $24. Write an equation that represents the number
wlad13 [49]
The equation is 24=23.50+0.25r
8 0
2 years ago
Let X be the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. The article "Methodo
Shkiper50 [21]

Answer:

a) P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.6288

P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.1954=0.4335

b) P(4\leq X\leq 8)=0.1954+0.1563+0.1042+0.0595+0.0298=0.5452

c) P(X \geq 8) = 1-P(X

d) P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559

Step-by-step explanation:

Let X the random variable that represent the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. We know that X \sim Poisson(\lambda=4)

The probability mass function for the random variable is given by:

f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...

And f(x)=0 for other case.

For this distribution the expected value is the same parameter \lambda

E(X)=\mu =\lambda=4  , Var(X)=\lambda=2, Sd(X)=2

a. Compute both P(X≤4) and P(X<4).

P(X\leq 4)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)+P(X=4)

Using the pmf we can find the individual probabilities like this:

P(X=0)=\frac{e^{-4} 4^0}{0!}=e^{-4}=0.0183

P(X=1)=\frac{e^{-4} 4^1}{1!}=0.0733

P(X=2)=\frac{e^{-4} 4^2}{2!}=0.1465

P(X=3)=\frac{e^{-4} 4^3}{3!}=0.1954

P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954

P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.9646

P(X< 4)=P(X\leq 3)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)

P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.5311=0.7692

b. Compute P(4≤X≤ 8).

P(4\leq X\leq 8)=P(X=4)+P(X=5)+ P(X=6)+P(X=7)+P(X=8)

P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954

P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563

P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042

P(X=7)=\frac{e^{-4} 4^7}{7!}=0.0595

P(X=8)=\frac{e^{-4} 4^8}{8!}=0.0298

P(4\leq X\leq 8)=0.1954+0.1563+ 0.1042+0.0595+0.0298=0.5452

c. Compute P(8≤ X).

P(X \geq 8) = 1-P(X

P(X \geq 8) = 1-P(X

d. What is the probability that the number of anomalies exceeds its mean value by no more than one standard deviation?

The mean is 4 and the deviation is 2, so we want this probability

P(4\leq X \leq 6)=P(X=4)+P(X=5)+P(X=6)

P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954

P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563

P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042

P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559

4 0
3 years ago
Simplifying algebraic expressions -8(2k-7)
son4ous [18]
-16k+56 check photo for steps and please mark as brainliest if i helped! thanks c:

8 0
3 years ago
Read 2 more answers
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