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vodka [1.7K]
3 years ago
13

Please answer this question fast in two minutes

Mathematics
2 answers:
Elodia [21]3 years ago
8 0

Answer:

S = (3, 5 )

Step-by-step explanation:

Given the endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

[ \frac{1}{2} (x₁ + x₂ ), \frac{1}{2} (y₁ + y₂ ) ]

let the coordinates of S be (x, y ), then using the midpoint formula equate the parts to the coordinates of the midpoint M

x = \frac{1}{2} (x + 5) = 4 ( multiply both sides by 2 )

x + 5 = 8 ( subtract 5 from both sides )

x = 3

y = \frac{1}{2} (y + 3) = 4 ( multiply both sides by 2 )

y + 3 = 8 ( subtract 3 from both sides )

y = 5

The coordinates of S = (3, 5 )

tatuchka [14]3 years ago
7 0

Answer:

the answer is (3,5)

Step-by-step explanation:

i used the slope between M and T to figure out where point S was

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On a piece of paper graph......
Artyom0805 [142]
Answer:

I think it’s the first one, A
6 0
3 years ago
Please someone help me to prove this. ​
morpeh [17]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ

Use the Sum/Difference Identities:

sin(α + β) = sinα · cosβ + cosα · sinβ

cos(α - β) = cosα · cosβ + sinα · sinβ

Use the Unit circle to evaluate: sin45 = cos45 = √2/2

Use the Double Angle Identities:   sin2Ф = 2sinФ · cosФ

Use the Pythagorean Identity: cos²Ф + sin²Ф = 1

<u />

<u>Proof LHS → RHS</u>

LHS:                                  2sin(45 + 2A) · cos(45 - 2A)

Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)

Unit Circle:    2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]  

Expand:        2[(1/2)cos²2A  + cos2A·sin2A + (1/2)sin²2A]

Distribute:              cos²2A   + 2cos2A·sin2A + sin²2A  

Pythagorean Identity:    1 + 2cos2A·sin2A

Double Angle:                1 + sin4A

LHS = RHS:  1 + sin4A = 1 + sin4A   \checkmark

6 0
3 years ago
WILL GIVE BRAINLIEST
Alona [7]

Given:

One linear function represented by the table.

Another linear function represented by the graph.

To find:

The greater unit rate and greater y-intercept.

Solution:

Formula for slope (unit rate):

m=\dfrac{y_2-y_1}{x_2-x_1}

From the given table it is clear that the linear function passes through (0,5) and (5,15). The function intersect the y-axis at (0,15), so the y-intercept is 15.

m_1=\dfrac{15-5}{5-0}

m_1=\dfrac{10}{5}

m_1=2

So, the unit rate of first function is 2.

From the given graph it is clear that the linear function passes through (0,6) and (-4,0). The function intersect the y-axis at (0,6), so the y-intercept is 6.

m_2=\dfrac{0-6}{-4-0}

m_2=\dfrac{-6}{-4}

m_2=\dfrac{3}{2}

So, the unit rate of first function is \dfrac{3}{2}.

Now,

2>\dfrac{3}{2}

m_1>m_2

And,

15>6

Therefore, the greater unit rate of the two functions is 2. The greater y-intercept of the two functions is 15.

4 0
3 years ago
Read 2 more answers
Help me please i put 15 points i think that means it gives you 7 or 8 points??
castortr0y [4]

Answer:

Mean: 0.15125

Median: 0.05

Mode: .05

Range: 0.495

Hope this helps!

3 0
4 years ago
PLEASE HELP FAST!!!!!!!!!!!!!!!!!!!!!!!!!!!ASAP
AveGali [126]

Answer:

x=2.50

Step-by-step explanation:

But I am not sure if its positive or negative.

6 0
3 years ago
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