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UkoKoshka [18]
4 years ago
13

A chemist prepares a solution by adding 293 mgmg of K2Cr2O7K2Cr2O7 (MWMW = 294.19 g/molg/mol ) to a volumetric flask, and then a

dding water until the total volume of the contents of the flask reaches the calibration line that indicates 250 mLmL . Determine the molarity of the prepared solution.
Chemistry
1 answer:
musickatia [10]4 years ago
8 0

Answer: The molarity of solution will be 0.00325 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute =\frac{\text{Given mass}}{\text{Molar mass}}

given mass = 239 mg = 0.239 g  (1g=1000mg)

moles of K_2Cr_2O_7=\frac{0.239g}{294.19g/mol}=8.12\times 10^{-4}mol

{V_s} = volume of solution in ml = 250 ml

Now put all the given values in the formula of molarity, we get

Molarity=\frac{8.12\times 10^{-4}\times 1000}{250ml}=3.25\times 10^{-3}mole/L

Therefore, the molarity of solution will be 0.00325 M

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