NH3 + O2 → NO + H2O How many moles of water are produced from 2.48 g of oxygen?

Chemistry

1 answer:

Dennis_Churaev [7]2 years ago

4 0

I hope this helps in some way. I forgot to mention that the question states they want to find THE NUMBER OF MOLES for H2O. Yherefore, you would want mol of H2O on top.

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How do you solve this ??

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Answer : Option A) 2.00 eV

Explanation : The conversion of J to eV is done with the following formula;

$E_{eV} = E_{J} X (6.241 X 10^{18})$

Here, we have the value of particle in terms of Joules which is 3.2 X $10^{-19}$

So, on substituting we get,
$E_{eV}$ = 3.2 X $10^{-19}$ X $(6.241 X 10^{18} )$

$E_{eV}$ = 1.99 eV so, it can be rounded off to 2.00 eV.

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3 years ago

__NH3 + __O2 → __NO + __H2O How many moles of water are produced from 2.48 g of oxygen?

NH3 + O2 → NO + H2O How many moles of water are produced from 2.48 g of oxygen?