Explain why crushed garlic has more flavor when put in food than a whole clove of garlic.
1 answer:
A crushed garlic will have a lot of flavor when placed in food due to the surface area that is in contact with the food. When we have a large piece of garlic, only the external part touches the food and its full capacity is not used. When we reduce the size of the year by crushing the internal parts that were not in contact with the food, now they will be, in addition, liquids are also released due to the pressure exerted on the garlic and these liquids mix more easily with the food and they give it more flavor. For better understanding we can see the following figure:
Simply to understand it, in the figure, there is a clove of whole garlic represented by the rectangle that will have a height of 3 and a width of 1, the units do not matter in this case. The area that is in contact will be equal to 8, but if we divide the garlic into three equal parts, it will have a contact area greater than 12. Therefore, the more we divide the garlic, the more area it will be in contact with the food and will give it more flavor.
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Answer:
Explanation:
The total mole of added = 15 × 1 × 10⁻³
= 15 × 10⁻³ mole
= 15 mmoles
the number of moles of NaOH added in order to neutralize the excess acid = 0.5905 × 29.393 = 17.36 mmoles
the equation for the reaction is:
2NaOH + -------->
i.e
2 moles of NaOH react with
1 moles of NaOH will react with 1/2
17.36 mmoles of NaOH = 1/2 × 17.36 mmoles of
= 8.68 mmoles
Number of moles of that react with MCO₃ = Total moles of
added - moles of
reacted with NaOH
= (15 - 8.68) mmoles
= 6.32 mmoles
+
------>
+
+
1 mole of react with 1 mole of
6.32 mmoles of = 6.32 mmoles of
number of moles of = 6.32 10⁻³ moles
mass of (carbonate salt) = 0.533 g
molar mass of = (M+60)g/mol
We all know that ;
number of moles = mass/molar mass
Then:
6.32 10⁻³ = 0.533 / (M+60)
(M+60) = 0.533/ 6.32 10⁻³
M + 60 = 84.34
M = 84.34 - 60
M = 24.34
Thus the element with the atomic mass of 24.34 is Chromium
The chemical formula for the compound is :