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1 year ago

Explain why crushed garlic has more flavor when put in food than a whole clove of garlic.

1 answer:

5 0

A crushed garlic will have a lot of flavor when placed in food due to the surface area that is in contact with the food. When we have a large piece of garlic, only the external part touches the food and its full capacity is not used. When we reduce the size of the year by crushing the internal parts that were not in contact with the food, now they will be, in addition, liquids are also released due to the pressure exerted on the garlic and these liquids mix more easily with the food and they give it more flavor. For better understanding we can see the following figure:

Simply to understand it, in the figure, there is a clove of whole garlic represented by the rectangle that will have a height of 3 and a width of 1, the units do not matter in this case. The area that is in contact will be equal to 8, but if we divide the garlic into three equal parts, it will have a contact area greater than 12. Therefore, the more we divide the garlic, the more area it will be in contact with the food and will give it more flavor.

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If you don't keep giving a car gas, the car will eventually stop. *

Strike441 [17]

Answer:

newtons 2nd law is the answer

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3 years ago

Enter your answer in the provided box. The atomic masses of 63Cu (69.17 percent) and 65Cu (30.83 percent) are 62.94 and 64.93 am

dybincka [34]

Answer: The average atomic mass of copper is 63.55 amu.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

For $_{29}^{63}\textrm{Cu}$ isotope:

Mass of $_{29}^{63}\textrm{Cu}$ isotope = 62.94 amu

Percentage abundance of $_{29}^{63}\textrm{Cu}$ = 69.17 %

Fractional abundance of $_{29}^{63}\textrm{Cu}$ isotope = 0.6917

For $_{29}^{65}\textrm{Cu}$ isotope:

Mass of $_{29}^{65}\textrm{Cu}$ isotope = 64.93 amu

Percentage abundance of $_{29}^{65}\textrm{Cu}$ = 30.83 %

Fractional abundance of $_{29}^{65}\textrm{Cu}$ isotope = 0.3083

Putting values in equation 1, we get:

$\text{Average atomic mass of Copper}=[(62.94\times 0.6917)+(64.93\times 0.3083)]\\\\\text{Average atomic mass of copper}=63.55amu$

Hence, the average atomic mass of copper is 63.55 amu.

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3 years ago

Which answer best describes an alpha particle

scZoUnD [109]

A positively charged nucleus with two protons and two neutrons hope this helps :)

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2 years ago

Particles of a liquid

Tcecarenko [31]

Answer:

Explanation:

B. That's a solid

C. Liquid is the only thing that can have viscosity

D. Not necessarily the case

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3 years ago

300 mL of 0.200 M Pb(NO3)2 is added to 200 mL of 0.0500 M NaCl(aq) at 25°C. Will a precipitate of PbCl2 form at 25 °C? Tip: You

Bas_tet [7]

Explanation:

It is given that volume of $Pb(NO_{3})_{2}$ is 300 mL and molarity is 0.200 M.

Volume of NaCl is 200 mL and molarity is 0.050 M.

The chemical reaction will be as follows.

$PbCl_{2}(s) \rightleftharpoons Pb^{2+}(aq) + 2Cl^{-}(aq)$

$K_{sp}$ for $PbCl_{2}$ is given as $1.7 \times 10^{-5}$ .

As, molarity is number of moles present in liter of solution.

Hence, moles of $Pb^{2+}$ (aq) will be calculated as follows.

moles of $Pb^{2+}$ (aq) = $0.300 L \times 0.200 M$

= 0.06 mol

$[Pb^{2+}]$ = $\frac{0.06 mol}{0.5 L}$

= 0.120 M

Mole of $Cl^{-}(aq)$ = $0.2 L \times 0.05 M$

= 0.010 M

Now, Q = $[Pb^{2+}][Cl^{-}]^{2}$

= $0.120 \times (0.010)^{2}$

= $1.2 \times 10^{-5}$

As, Q < $K_{sp}$ hence, there will be no formation of $PbCl_{2}$ precipitate.

3 0

3 years ago