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Furkat [3]
3 years ago
10

Formation of magnesium chloride​

Chemistry
1 answer:
Shkiper50 [21]3 years ago
5 0

-Pure magnesium is commonly made by separating it from seawater. This process is known as electrolysis. The liquid magnesium formed is cooled into convenient blocks of metal known as ingots. The chlorine gas is recycled to form hydrochloric acid for the production of more magnesium chloride.

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I will reward Brainly please help
laila [671]
By crushing a solid into a powder you increase the reaction rate (the chemical reaction rate). By crushing into a powder, you are increasing the surface area, increasing the exposure to the chemical reaction. The smaller the particles, the faster the chemical reaction that will take place. Think about an ice cube put in a pot of boiling water. The whole ice cube will take longer to melt than if you first crushed that ice cube into small pieces. Small pieces of ice put into boiling water would melt very quickly.

Hope this helps!! :)
7 0
3 years ago
A 0.2 m solution of a weak acid ha dissociates such that 99.4% of the weak acid remains intact (i.e., remains as ha). what is th
Kobotan [32]
HA -----> H(+) + A(-)
0,2-x.........x..........x

100% - 99,4% = 0,6% = 0,006

x = 0,6%×0,2 = 0,006 × 0,2 = 0,0012

HA --------------> H(+) + A(-)
0,2-x.....................x..........x
0,2-0,0012.....0,0012..0,0012
0,1988.............0,0012..0,0012

K = [H+][A-]/[HA]
K = (0,0012)^2/0,1988
K = 0,0000072434

pKa = -logK= -log0,0000072434 = 5,14

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3 0
3 years ago
The color of a star could give hints to<br><br> mass<br> temperature<br> brightness<br> density
Elza [17]
It’s basically just mass
7 0
3 years ago
Read 2 more answers
an empty relative density bottle weights 20g. the bottle weights 40g when filled with petrol and 60g when filled with water. det
Kobotan [32]

Answer:

500 Kg/m³

Explanation:

From the question given above, the following data were obtained:

Mass of empty bottle = 20 g

Mass of bottle + petrol = 40 g

Mass of bottle + water = 60 g

Density of water = 1000 Kg/m³

Density of petrol =?

Next, we shall determine the mass of water. This can be obtained as follow:

Mass of empty bottle = 20 g

Mass of bottle + water = 60 g

Mass of water =?

Mass of water = (Mass of bottle + water) – (Mass of empty bottle)

Mass of water = 60 – 20

Mass of water = 40 g

Converting 40 g to Kg, we have:

1000 g = 1 Kg

Therefore,

40 g = 40 × 1 Kg / 1000 g

40 g = 0.04 Kg

Next, we shall determine the volume of the bottle by calculating the volume of water. This can be obtained as follow:

Mass of water = 0.04 Kg

Density of water = 1000 Kg/m³

Volume of water =?

Density = mass / volume

1000 = 0.04 / volume

Cross multiply

1000 × volume = 0.04

Divide both side by 1000

Volume of water = 0.04 / 1000

Volume of water = 4×10¯⁵ m³

Thus, the volume of the bottle is 4×10¯⁵ m³

Next, we shall determine the mass of the petrol. This can be obtained as follow:

Mass of empty bottle = 20 g

Mass of bottle + petrol = 40 g

Mass of petrol =?

Mass of petrol = (Mass of bottle + petrol ) – (Mass of empty bottle)

Mass of petrol = 40 – 20

Mass of petrol = 20 g

Converting 20 g to Kg, we have:

1000 g = 1 Kg

Therefore,

20 g = 20 × 1 Kg / 1000 g

20 g = 0.02 Kg

Finally, we shall determine the density of the petrol. This can be obtained as follow:

Mass of petrol = 0.02 Kg

Volume of petrol = 4×10¯⁵ m³

Density of petrol =?

Density = mass / volume

Density of petrol = 0.02 / 4×10¯⁵

Density of petrol = 500 Kg/m³

4 0
3 years ago
Add oxidation numbers to the following reaction: 2 H3PO4 (aq) + 2 Cr(s) → 2 CrPO4 (aq) + 3 H2(g). Identify the atom that is oxid
rewona [7]

The atom that is oxidized : Cr

The oxidizing agent : H₃PO₄

<h3>Further explanation</h3>

Reaction

2 H₃PO₄ (aq) + 2Cr(s) → 2 CrPO₄ (aq) + 3H₂(g)

Atoms undergoing a reduction reaction (decrease in oxidation number) and an oxidation reaction (increase in oxidation number)

  • Reduction (+1 to 0)

H⁺(in H₃PO₄) =+1

H₂=0

  • Oxidation (0 to +3)

Cr = 0

Cr³⁺(in CrPO₄ )

the oxidizing agent.⇒which undergoes a reduction reaction and oxidizes another compound/element : H₃PO₄

3 0
3 years ago
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