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3 years ago

Formation of magnesium chloride

1 answer:

5 0

-Pure magnesium is commonly made by separating it from seawater. This process is known as electrolysis. The liquid magnesium formed is cooled into convenient blocks of metal known as ingots. The chlorine gas is recycled to form hydrochloric acid for the production of more magnesium chloride.

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The exhaust gas from an automobile contains 1.5 percent by volume of carbon monoxide. What is the concentration of CO in mg/m' a

FrozenT [24]

Answer:

(a) 17,178 mg/m3

(b) 11,625 mg/m3

Explanation:

The concentration of CO in mg/m3 can be calculated as

$C (mg/m3) =(P/RT)*MW*C_{ppm}$

For standard conditions (1 atm and 25°C), P/RT is 0.0409.

Concentration of 1.5% percent by volume of CO is equivalent to 1.5*10,000 ppm= 15,000 ppm CO.

The molecular weigth of CO is 28 g/mol.

(1) For 25°C and 1 atm conditions

$C=(P/RT)*MW*C_{ppm}\\\\C=0.0409*28*15,000=17,178$

(b) For 200°C and 1.1 atm,

$P/RT=0.0409*(P/P_{std})*(T_{std}/T)\\P/RT=0.0409*(1.1atm/1atm)*(273+15K/273+200K)=0.0277$

Then the concentration in mg/m3 is

$C=(P/RT)*MW*C_{ppm}\\\\C=0.0277*28*15,000=11,625$

5 0

3 years ago

What are some main points about star formation

AysviL [449]

Explanation:

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3 years ago

What are the main 3 gases from the greenhouse affect.

andrezito [222]

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4 years ago

Read 2 more answers

How much volume will 8.8 moles of gas fill at 0.12 atm at 56*C

Neporo4naja [7]

Answer:

2000 L

General Formulas and Concepts:

Atomic Structure

Moles
Temperature Conversion: K = °C + 273.15

Gas Laws

Ideal Gas Law: PV = nRT

P is pressure
V is volume (in L)
n is number of moles
R is gas constant
T is temperature (in K)

Explanation:

Step 1: Define

[Given] 8.8 moles gas

[Given] 0.12 atm

[Given] 56 °C = 329.15 K

Step 2: Solve for V

Substitute in variables [Ideal Gas Law Formula]: $\displaystyle (0.12 \ atm)V = (8.8 \ mol)(0.0821 \ \frac{L \cdot atm}{mol \cdot K})(329.15 \ K)$
Isolate V: $\displaystyle V = \frac{(8.8 \ mol)(0.0821 \ \frac{L \cdot atm}{mol \cdot K})(329.15 \ K)}{(0.12 \ atm)}$
Multiply/Divide [Cancel out units]: $\displaystyle V = 1981.7 \ L$

Step 3: Check

Follow sig fig rules and round. We are given 2 sig figs.

1981.7 L ≈ 2000 L

3 0

3 years ago

Calculate the number of moles of Li3PO4 in 2.2 L of a 0.60 M Li3PO4 solution.

Bingel [31]

Answer:

1.32 mole

Explanation:

The following data were obtained from the question:

Volume of solution = 2.2L

Molarity of solution = 0.60M

Mole of Li3PO4 =..?

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is represented as:

Molarity = mole /Volume

With the above formula we can easily calculate the number of mole of Li3PO4 as shown below:

Molarity =mole /Volume

0.6 = mole of Li3PO4 /2.2

Cross multiply

Mole of Li3PO4 = 0.6 x 2.2

Mole of Li3PO4 = 1.32 mole

Therefore, 1.32 mole of Li3PO4 is contained in the solution.

4 0

3 years ago

Formation of magnesium chloride​

Formation of magnesium chloride