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nlexa [21]
3 years ago
14

The total amount of fresh water on earth is estimated to be 3.73 x 10^8 km^3. What is this volume in cubic meters? in cubic feet

?
Physics
2 answers:
Brilliant_brown [7]3 years ago
6 0

The total amount of fresh water on earth is 3.73 *10^{8} km^3

 Hence the volume of water v= 3.73*10^{8} km^{3}

we are asked to convert this into cubic metre and cubic feet.

we know that 1 km = 1000 m.

                     1 km^3 = [10^3 m]^3

                     1 km^3 = 10^{9} m^{3}

       we have been given  v = 3.73 *10^{8} km^3

                                            v = 3.73 *10^{8} *10^{9} m^{3}      

                                              v = 3.73*10^{17} m^{3}  [ANS]

Now we have to  convert it into cubic feet

we know that one metre =  3.28083 feet

                   1 m^{3} =[3.28083feet]^{3}

                    1 m^{3} =35.3143472 feet^{3}

         Hence  v =3.73*10^{17} m^{3}

                       = 3.73*10^{17} *35.3143472 feet^{3}

                  ⇒  v = 131.7225*10^{17} feet^{3}  [ANS]

Burka [1]3 years ago
5 0
One km^3 is 1,000,000,000 m^3=10^9 m^3 hence 3.73 10^8 km^3 is 3.73 10^17 m^3

One meter is 3.28084 feet hence 1 m^3 is (3.28084)^3 feet

Thus 3.73 10^8 km^3 is 3.73*35.315 10^17 = 132 cubic feet
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Expxlanation:

Step 1:

Data obtained from the question. This includes:

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Finding an expression to calculate the diameter of the ball. This is illustrated below:

Tension = weight displaced - weight of the ball

Weight displaced = Mass of water x acceleration due to gravity

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Make V the subject of the formula

T = ρVg - mg

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Recall that the ball is spherical in shape and the Volume of a sphere is given by

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V = ( T + mg) /ρg

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Making d the subject of the formula, we have:

πd^3 /6 = (T + mg) /ρg.

d^3 = 6(T + mg) /πρg.

Taking the cube root of both sides

d = [6(T + mg) /πρg]^1/3

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Determination of the diameter of the ball. This is illustrated below:

T = 0.029 N

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d =?

d = [6(T + mg) /πρg]^1/3

d = [6(0.029 + 2.5x10^-3x9.81)/ πx1000x9.81]^1/3

d = 0.022m

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The volume of the rod is 1.26×10⁻⁵ m³, and the linear charge density of the rod is 3.64 C/m

<h3>What is volume?:</h3>

This is the product of the height of a solid object and its crossectional area.

The Volume of the rod is can be calculated using the formula below.

Note: A rod has the shape of a cylinder.

Formula:

  • V = πr²h............... Equation 1

Where:

  • V = Volume of the rod
  • r = radius of the rod
  • h = height of the rod.

From the question,

Given:

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Substitute these values into equation 1

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<h3>What is linear charge density:</h3>

This is the ratio of the charge on an object to the length of the object.

The linear charge density of the rod can be calculated using the formula below.

  • D = Q/h.................... Equation 2

Where:

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  • Q = Charge on the rod.
  • h = height or length of the rod

From the question

Given:

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Substitute these values into equation 2

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Hence, The volume of the rod is 1.26×10⁻⁵ m³, and the linear charge density of the rod is 3.64 C/m

Learn more about charge density here: brainly.com/question/14568868

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