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beks73 [17]
3 years ago
11

Which statements apply to transverse waves? Check all that apply.

Physics
2 answers:
Levart [38]3 years ago
8 0

Correct Answers:

- The waves have a trough

- the waves have a crest

- the energy that is transferred move in a perpendicular direction

- particles move in an up and down motion

Gennadij [26K]3 years ago
6 0

Answer:

A, c, d, e

Explanation:

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The gravitational force between Pluto and Charon is 3.61 × 1018 N. Pluto has a mass of 1.3 × 1022 kg, which is only slightly gre
raketka [301]

<u>Answer:</u>

<em>The distance between Pluto and Charon is  1.96 \times 10^7  m</em>

<u>Explanation:</u>

Force of gravitation between two objects F_g= \frac{G(M_1 M_2 )}{r^2}  

Where M_1  \ and \ M_2  are the masses of the objects,r is the distance between the objects

G is the universal gravitational constant=6.67 \times 10^-^1^1 m^3/kg s^2

Here mass of pluto = 1.3 \times 10^2^2  kg

mass of charon = 1.6 \times 10^2^1 kg

Force of gravitation F_g=3.61 \times 10^1^8  N

F_g= \frac {G(M_1 M_2 )}{r^2}

r^2= \frac {G(M_1 M_2 )}{F_g }

r= \sqrt \frac{(G(M_1 M_2 )}{F_g}

=\sqrt \frac {((6.674\times 10^-^1^1) \times 1.3 \times 10^2^2 \times 1.6\times 10^2^1)}{(3.61 \times 10^1^8 )}

=\sqrt \frac {(13.88*10^32)}{(3.61*10^18)}

=1.96 \times10^7  m

4 0
4 years ago
Read 2 more answers
Give examples of factors or criteria often used to determine higher wages for a particular job
marshall27 [118]
-- the applicant's previous experience at similar jobs;
-- the color of the applicant's hair;
-- the applicant's grammar and vocabulary;
-- where the applicant went to school;
-- the shirt the applicant wears to the job interview;
-- the applicant's favorite football team;
-- the applicant's self-confidence;
5 0
3 years ago
Read 2 more answers
a car accelerates along a straight road from rest to 75km/h in 5.0s. What is the magnitude of its average acceleration? show up
kykrilka [37]

Answer:

4.186 m/s^2

Explanation:

First, convert km/hr to m/s:

(75 km/hr)(1000m/1km)(1hr/60min)(1min/60s) = 20.83 m/s

Then, divide 20.93 m/s by 5.0s

(20.93 m/s) / (5.0s) = 4.186 m/s^2

5 0
3 years ago
Use the chart to determine the half-life of carbon-14
lubasha [3.4K]

The correct answer to the question is B) 5,700 years.

EXPLANATION:

Before going to answer this question, first we have to understand half life period of a radio active substance.

The half life period [\ T_{1/2}\ ] of a radio active substance is defined as the time in which half of the radio active specimen has undergone decay.

As per the question, the initial concentration of the radioactive carbon-14 is given as 10,000.

Hence, initial concentration N_{0} =\ 10,000.

After 5,700 years, the remaining radio active specimen is 5000. It means that half of the radio active specimen has undergone decay in 5,700 years.

Hence,  half life period of the radio active carbon-14 specimen is 5,700 years.

7 0
3 years ago
Read 2 more answers
Which type of thunderstorm is the largest in terms of size and area covered?
Scrat [10]

Answer:

b. Thunderstorm, Mesoscale

Explanation:

The Mesoscale convective system is a quite wide orbit, or perhaps a thunderstorm system. This is not a specific thunderstorm but various thunderstorms have combined and function as one huge system. It can consume up to 100 km of space. These thunderstorms can lead to a number of difficulties, and since they are a mixture of different thunderstorm types, they can expect pretty much everything.

4 0
4 years ago
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