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Tpy6a [65]
3 years ago
14

Liz puts a 1 kg weight and a 10 kg on identical sleds. She then applies a 10N force to each sled. Describe why the smaller weigh

t has a larger acceleration. A) There is same amount force is applied to both sleds. B) The acceleration is directly proportional to the force. C) It indicates the extent of the unbalanced forces present. D) Acceleration depends indirectly on the mass of the object.
Physics
2 answers:
elena-14-01-66 [18.8K]3 years ago
8 0

the correct answer is D- Acceleration depends indirectly on the mass.

According to Newton's second law, the force F, the mass m and the acceleration a are related as follows:

F=ma

Therefore,

a=\frac{F}{m}

The acceleration <em>a₁ </em>of the mass<em> m₁ =1 kg</em>  is given by,

a_1=\frac{F}{m_1} \\ =\frac{10N}{1kg} \\ =10m/s^2

The acceleration <em>a₂ </em>of the mass <em>m₂=10 kg</em> is given by,

a_2=\frac{10N}{10kg} \\ =1m/s^2

The smaller mass has greater acceleration.

Thus, when the force applied on two bodies of different masses remains constant, then,

a\alpha  \frac{1}{m}

Acceleration is inversely proportional to the mass of the body.



laiz [17]3 years ago
8 0

the answer is D i had the test

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Arte-miy333 [17]
I attached the picture of the missing table.
Center of mass is the point such that if you apply force to it, the system would move without rotating.
We can use following formula to calculate the center of mass:
R=\frac{1}{M}\sum_{i=1}^{n=i}m_ir_i
Where M is the sum of the masses of all particles.
Part 1
To calculate the x coordinate of the center of mass we will use this formula:
R_x=\frac{1}{M}\sum_{i=1}^{n=i}m_ix_i
I will do all the calculations in the google sheet that I will share with you.
For the x coordinate of the center of mass we get:
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Part 2
To calculate the y coordinate of the center of mass we will use this formula:
R_y=\frac{1}{M}\sum_{i=1}^{n=i}m_iy_i
I will do all the calculations in the google sheet that I will share with you.
For the x coordinate of the center of mass we get:
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Part 3
We will calculate speed along x and y-axis separately and then will add them together.
v_x=\frac{\sum_{i=1}^{n=i}m_iv_x_i}{M}
v_y=\frac{\sum_{i=1}^{n=i}m_iv_y_i}{M}
Total velocity is:
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Once we calculate velocities we get:
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Part 4
Because origin is left to our center of mass(please see the attached picture) placing fifth mass in the origin would move the center of mass to the left along the x-axis.
Part 5
If you place fifth mass in the center of the mass nothing would change. The center of mass would stay in the same place.
Here is the link to the spreadsheet:
https://docs.google.com/spreadsheets/d/1SkQHbI1BxiJnwpWbLmP0XWgcNPrGquH1K2MfN6cznVo/edit?usp=sharing

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