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Tpy6a [65]
3 years ago
14

Liz puts a 1 kg weight and a 10 kg on identical sleds. She then applies a 10N force to each sled. Describe why the smaller weigh

t has a larger acceleration. A) There is same amount force is applied to both sleds. B) The acceleration is directly proportional to the force. C) It indicates the extent of the unbalanced forces present. D) Acceleration depends indirectly on the mass of the object.
Physics
2 answers:
elena-14-01-66 [18.8K]3 years ago
8 0

the correct answer is D- Acceleration depends indirectly on the mass.

According to Newton's second law, the force F, the mass m and the acceleration a are related as follows:

F=ma

Therefore,

a=\frac{F}{m}

The acceleration <em>a₁ </em>of the mass<em> m₁ =1 kg</em>  is given by,

a_1=\frac{F}{m_1} \\ =\frac{10N}{1kg} \\ =10m/s^2

The acceleration <em>a₂ </em>of the mass <em>m₂=10 kg</em> is given by,

a_2=\frac{10N}{10kg} \\ =1m/s^2

The smaller mass has greater acceleration.

Thus, when the force applied on two bodies of different masses remains constant, then,

a\alpha  \frac{1}{m}

Acceleration is inversely proportional to the mass of the body.



laiz [17]3 years ago
8 0

the answer is D i had the test

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Consider a series rlc circuit where r = 45.0 ω, c = 15.5 μf, and l = 0.0940 h, driven at a frequency of 50.0 hz. determine the p
givi [52]
R = 45 \ \Omega. \newline C = 15.5 \ \mu F = 15.5 \cdot 10^{-6} \ F.\newline l = 0.0940 \ H.\newline \nu = 50 \ Hz. \newline \newline x_{l} = 2 \pi \nu l = 2 \pi \cdot 50 \cdot 0.0940 = 29.5309709437 \approx 29.5 \ \Omega. \newline x_{c} = \frac{1}{2 \pi C \nu} = \frac{1}{2 \pi \cdot 15.5 \cdot 10^{-6} \cdot 50} = 0.00486946861 \approx 0.005 \ \Omega. \newline Z = \sqrt{R^{2}+(x_{l}-x_{c})^{2}} = \sqrt{45^{2}+(29.5-0.005)^{2}} = 53.8047862648 \approx 54 \ \Omega. \newline \newline \cos(\theta) = \frac{R}{Z} = \frac{45}{54} = 0.8\bar{3} \Rightarrow \arccos(0.8\bar{3}) = 33.5573098 \approx 33.5 \textdegree.
7 0
4 years ago
Which scenario is an application of Newtons Second Law of Motion?
svlad2 [7]
D would be the answer because The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
4 0
3 years ago
consider two stars, star a and star b. star a has a temperature of 4900 k , and star b has a temperature of 9900 k . how many ti
ValentinkaMS [17]

The Energy flux from Star B is 16 times of the energy flux from Star A.

We have Two stars - A and B with 4900 k and 9900 k surface temperatures.

We have to determine how many times larger is the energy flux from Star B compared to the energy flux from Star A.

<h3>State Stephen's Law?</h3>

Stephens law states that if E is the energy radiated away from the star in the form of electromagnetic radiation, T is the surface temperature of the star, and σ is a constant known as the Stephan-Boltzmann constant then-

$\frac{Energy}{Area} = \sigma\times T^{4}

Now -

Energy emitted per unit surface area of Star is called Energy flux. Let us denote it by E. Then -

$E= \sigma\times T^{4}

Now -

For Star A →

T_{A} = 4900 K

For Star B →

T_{B} = 9900 K

Therefore -

$\frac{T_{B} }{T_{A} } =\frac{9900}{4900}

\frac{T_{B} }{T_{A} }= 2.02 = 2 (Approx.)

Now -

Assume that the energy flux of Star A is E(A) and that of Star B is E(B). Then -

$\frac{E(B)}{E(A)} = \frac{\sigma\times T(B)^{4} }{\sigma \times T(A)^{2} }

E(B) = E(A) x (\frac{T(B)}{T(A)} )^{4}

E(B) = E(A) x 2^{4}

E(B) = 16 E(A)

Hence, the Energy flux from Star B is 16 times of the energy flux from Star A.

To learn more about Stars, visit the link below-

brainly.com/question/13451162

#SPJ4

4 0
2 years ago
What is measured in watts that starts with a p
Nesterboy [21]
Power is measured in watts
6 0
3 years ago
A hockey goalie is standing on ice. Another player fires a puck (m = 0.170 kg) at the goalie with a velocity of +41.0 m/s. (a) I
viktelen [127]

Answer:

2991.42 N

Explanation:

For this problem, we'll use the equations: momentum= mass x velocity and impulse = change in momentum, and impulse=force x time.

initial momentum; p1 = 0.17 x 41 = 6.97 kg.m/s

final momentum; p2 = 0, because final velocity is 0 m/s

Thus,

impulse = p1 - p2= 6.97 - 0 = 6.97 kg.m/s

Finally, impulse= Force x time,

Thus, Force = Impulse/time

Force= 6.97/ (2.33 x 10^(-3)) = 2991.42 N

4 0
4 years ago
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