The final momentum of the ball is 3.8 kgm/s.
<h3>Change in momentum of the ball</h3>
The impulse received by the ball is equal to change in momentum of the ball.
J = ΔP
where;
- J is the impulse
- ΔP is change in momentum
ΔP = P₂ - P₁
P₂ = ΔP + P₁
<h3>Final momentum of the ball</h3>
The final momentum of the ball is calculated as follows;
P₂ = 8 + (- 0.1 x 42)
P₂ = 8 - 4.2
P₂ = 3.8 kgm/s
Learn more about change in momentum here: brainly.com/question/7538238
Answer:
An object is called a horizontal projectile if it is launched from a certain height with some initial horizontal velocity only. The initial vertical velocity of such an object is zero. But as the object falls through the atmosphere the horizontal component of velocity remains constant but vertical component increases due to gravitational acceleration.
Explanation:
Answer:
1) Time interval Blue Car Red Car
0 - 2 s Constant Velocity Increasing Velocity
2 - 3 s Constant Velocity Constant Velocity
3 - 5 s Constant Velocity Increasing Velocity
5 - 6 s Constant Velocity Decreasing Velocity
2) For Red and Blue car y₂ = 120 v =
=
= 20 m/s
We get the same velocity for two cars because it is the average velocity of the car at the given interval of time. It is measured for initial and final position.
3) At t = 2s, the cars are the same position, and are moving at the same rate
Position - same
Velocity - same
The position-time graph shares the same spot for two cars.