A 46- inch piece of steel is cut into three pieces so that the second piece is twice as long ad the first piece , and the third
piece is one inch more than six times the length of the first piece. Find the lengths of the pieces.
1 answer:
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Answer:
x=
Step-by-step explanation:
47(218 x+12 ) =−2(17 −528 x)
Simplify 47(218 x+12 ) : 327(21x+4) 327(21x+4) =−2(17 −528 x)
Multiply both sides by 7(21x+4)
327(21x+4) · 7(21x+4)=−2(17 −528 x)· 7(21x+4)
Simplify, 32=−14(17 −528 x)(21x+4)
Solve 32=−14(17 −528 x)(21x+4): x=32+4√589105 , x=32−4√589105 x=32+4√589105 , x=32−4√589105