Answer:
1. $250,000× 6,5%= $16,250
$310,000×6,5% = $20,150
therefore $16,250+$20,150=$21,800
2
991,000 times ×$1,09×15% = $162,028.5
Step-by-step explanation:
3. $8,870×25%=$2217,50
Answer:
30x³
Step-by-step explanation:
2x×3x=6x²
6x²×5x=30x³
Answer:
The given system as (3,3) as its solution.
Step-by-step explanation:
Here, the given system of the equation is:
4 x + 2 y = 18
................ (1)
2 x + 3 y = 15 ............... (2)
Now, to use the elimination method, w need to eliminate any of the variable.
Eliminate the variable x in the given system.
Multiply equation (2) with -2 we get,
(2 x + 3 y = 15 )(-2) ⇒ -4x - 6y = -30 ....... (3)
Add (1) and (3), we get:
4 x + 2 y -4x - 6y = 18 -30
or, - 4 y = - 12
or, y = 12/4 = 3 ⇒ y = 3
Putting in (1), we get
4x + 2(3) = 18 or, 4x = 18 - 6 = 12
or, x = 3
(x,y) = (3,3)
Hence, the above system as (3,3) as its solution.
<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
The rule of geometric sequence is ⇒⇒⇒ a * r^(n-1)
Where a is the first term and r is the common ratio
for the given sequence √5 , √10 , 2√5 , .......
a = √5
r = √10 / √5 = √2
The ninth term = √5 * (√2)^(9-1) = √5 * (√2)⁸ = 16 √5
the correct answer is the third option 16√5
