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kozerog [31]
2 years ago
6

Statistics when mode is best measure of central tendency.

Mathematics
1 answer:
ehidna [41]2 years ago
6 0

Answer:

The mode is the least used of the measures of central tendency

Step-by-step explanation:

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PLS HELP
german

Answer:

1. $250,000× 6,5%= $16,250

$310,000×6,5% = $20,150

therefore $16,250+$20,150=$21,800

2

991,000 times ×$1,09×15% = $162,028.5

Step-by-step explanation:

3. $8,870×25%=$2217,50

3 0
2 years ago
The edges of a rectangle solid have lengths 2x,3xand 5x.what is the total surface area of the solid ?
Greeley [361]

Answer:

30x³

Step-by-step explanation:

2x×3x=6x²

6x²×5x=30x³

8 0
2 years ago
Item 3
Kruka [31]

Answer:

The given  system as (3,3) as its solution.

Step-by-step explanation:

Here, the given system of the equation is:

4 x + 2 y = 18 ................  (1)

2 x + 3 y = 15      ...............  (2)

Now, to use the elimination method, w need to eliminate any of the variable.

Eliminate the variable x in the given system.

Multiply equation (2) with -2  we get,

(2 x + 3 y = 15  )(-2) ⇒ -4x - 6y = -30  .......  (3)

Add (1) and (3), we get:

4 x + 2 y   -4x - 6y    = 18  -30

or, - 4 y = - 12

or, y =  12/4 = 3    ⇒ y = 3

Putting in (1), we get

4x + 2(3)   = 18  or, 4x    = 18 - 6 = 12

or, x  = 3

(x,y)  = (3,3)

Hence, the above system as (3,3) as its solution.

6 0
2 years ago
At 3 p.m. an oil tanker traveling west in the ocean at 14 kilometers per hour passes the same spot as a luxury liner that arrive
schepotkina [342]
<span>N(t) = 16t ; Distance north of spot at time t for the liner. W(t) = 14(t-1); Distance west of spot at time t for the tanker. d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t. Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is N(t) = 16t Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is W(t) = 14(t-1) The distance between the 2 ships is easy. Just use the pythagorean theorem. So d(t) = sqrt(N(t)^2 + W(t)^2) If you want the function for d() to be expanded, just substitute the other functions, so d(t) = sqrt((16t)^2 + (14(t-1))^2) d(t) = sqrt(256t^2 + (14t-14)^2) d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) ) d(t) = sqrt(452t^2 - 392t + 196)</span>
3 0
3 years ago
Find the ninth term of the sequence sqrt 5, sqrt 10, ^2sqrt 5
hjlf
The rule of geometric sequence is   ⇒⇒⇒ a * r^(n-1)
Where a is the first term and  r is the common ratio
for the given sequence  √5 , √10 , 2√5 , .......
a = √5
r = √10 / √5 = √2
The ninth term = √5 * (√2)^(9-1) = √5 * (√2)⁸ = 16 √5

the correct answer is the third option 16√5
5 0
3 years ago
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