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Shalnov [3]
3 years ago
5

5r^2-44r+120 = -30r+11r

Mathematics
1 answer:
garik1379 [7]3 years ago
3 0
5r^2-44r+120 = -30r+11r \\ \\ 5f^2 - 44r + 120 = -19r \\ \\ 5r^2 - 44r + 120 + 19r = 0 \\ \\ 5r^2 - 25r + 120 = 0 \\ \\ r =  \frac{25+5 \sqrt{71i} }{10} ,  \frac{25-5 \sqrt{71i} }{10} \\ \\ r =  \frac{5+ \sqrt{71i} }{2} ,  \frac{5 -   \sqrt{71i}  }{2} \\ \\ ANSWER:  r =  \frac{5+ \sqrt{71i} }{2} ,  \frac{5 -   \sqrt{71i}  }{2}
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4 0
3 years ago
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6 0
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Read 2 more answers
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