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2 years ago

What is the volume of this sphere? 12pi cm^3 36pi cm^3 288pi cm^3 864pi cm^3

Mathematics

1 answer:

Verdich [7]2 years ago

3 0

Answer:

Option 3

Step-by-step explanation:

Volume of a sphere:

(4/3)×pi×r³

(4/3)pi × 6³

288pi cm³

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Can someone please help with my work

Leviafan [203]

Answer:

Step-by-step explanation:

41+77= 112

180-112= 68

The angles in a triangle all add up to 180°.

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2 years ago

Which descriptions can describe more than one triangle? check all that apply

babunello [35]

Answer:

Angle measurements of 35°, 35°, and 110°

Angle measurements of 40°, 60°, and 80°

Step-by-step explanation:

If you specify only the three angles, you can have an infinite number of similar triangles of different sizes.

A is wrong. There can be only one triangle in which all three side lengths are specified.

C is wrong. The angles do not add up to 180°.

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3 years ago

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6) The population of rats doubles every 8 months. If there were 23 rats to start how many

taurus [48]

Answer:

736

Step-by-step explanation:

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2 years ago

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a rectangle has an area of 102 cm2. the length of the rectangle is 17 cm. what is the perimeter of the rectangle?

Kruka [31]

Area = length *width

102 = 17*w

w = 102/17 = 6

l=17
w=6

perimeter = 2l +2w
p = 2(l+w)
p=2*23

p = 46 cm

hope helped

4 0

3 years ago

To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI

nadya68 [22]

Part 1) To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

Applying the law of sines

$\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}$

in this problem we have

$\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})$

therefore

the answer Part 1) is

Law of Sines

Part 2) To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

$g^{2}=h^{2}+i^{2}-2*h*i*cos\ G$

In this problem we have

g=HI

G=angle Beta

substitute

$HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta$

$HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}$

therefore

the answer Part 2) is

Law of Cosines

3 0

2 years ago

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