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UkoKoshka [18]
3 years ago
7

Consider the quadratic function f(x) = ax? + bx + 22. The equation of the axis of symmetry is

Mathematics
1 answer:
Triss [41]3 years ago
5 0

Answer:

nnnnnnnjj

Step-by-step explanation:

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Dolores is going to make a sandwich. She has 2 types of bread, 3 types of cheese, and 2 types of meat to choose from. How many d
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Twelve hours later then we went to sleep and then woke me back at my house after my birthday and I got invited
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The growth of 100 young trees near a river is given below. At most 50 yards from the river (Event Y) More than 50 yards from the
Alona [7]

Answer:

It is 91% more likely that the tree was atmost 500 yards from the river.

<h3>Step-by-step explanation:</h3>

We are given with distance and height of 100 young trees near a river.

From that table, in total there are 55 trees which grow more than 3 ft during the year.

And among those 55 trees, 50 trees are atmost 50 yards from river.

Hence it is ≈91% more likely that the tree was atmost 50 yards from the river.

4 0
3 years ago
6 cups is how many times as much as 24 cups?
kaheart [24]

Answer:

2 llllllllllllllllllllllllllllll

6 0
2 years ago
Read 2 more answers
Find the slope of the line passing through the points (0,12) and (4,3)
anzhelika [568]

The slope is the change in Y over the change in X:

Slope = (3 -12) / (4-0)

Slope = -9/4

The answer is the 3rd choice.

7 0
3 years ago
A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d
Sliva [168]

Answer:

There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

P(A) = P_{1} + P_{2} + P_{3}

In which P_{1} is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

P_{1} = 0.35*0.25 = 0.0875

P_{2} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{2} = 0.15*0.05 = 0.0075

P_{3} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{3} = 0.50*0.15 = 0.075

So

P(A) = 0.0875 + 0.0075 + 0.075 = 0.17

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

P = \frac{0.5*0.15}{0.17} = 0.4412

There is a 44.12% probability that the defective product came from C.

3 0
3 years ago
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