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Olin [163]
3 years ago
15

Is a box and whiskers chart divides a data set into 4 equal parts called quartiles

Mathematics
2 answers:
deff fn [24]3 years ago
8 0
In this section, we discuss box-and-whisker plots and the five key values ... The key values are called a five-number summary, which consists of the minimum, first quartile, ... the set is put into increasing order, divides the data into two equal parts. ... First, we put the values in the data set into increasing order: 3, 5, 7, 8, 12, 13, ... The middle score for a set of data that has been arranged in order from least to ... A box-and-whisker plot shows the distribution of a set of data along a ... Quartiles are values that divide a set of data into four equal parts. ... Second Quartile ( designated Q2) also called the median or the 50th percentile (cuts data set in half ).
Reptile [31]3 years ago
5 0
Yes, this statement is true.
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Please help me <br>what is the value of x+y
Norma-Jean [14]
The correct answer ic C)12
7 0
2 years ago
Read 2 more answers
48. Reading Rates The reading speed of sixth-grade students is approximately normal, with a mean speed of 125 words per minute a
son4ous [18]

Answer:

The reading speed of a sixth-grader whose reading speed is at the 90th percentile is 155.72 words per minute.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 125, \sigma = 24

What is the reading speed of a sixth-grader whose reading speed is at the 90th percentile

This is the value of X when Z has a pvalue of 0.9. So it is X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 125}{24}

X - 125 = 1.28*24

X = 155.72

The reading speed of a sixth-grader whose reading speed is at the 90th percentile is 155.72 words per minute.

4 0
3 years ago
Read 2 more answers
If Keira spends $45 on petrol, 1/ 9 of the money on other items and 1 /5 of the money on clothes. How much money does she spend
gogolik [260]

Answer:

The money Keira spent on food is $31.

Step-by-step explanation:

Total money spent by Keira = $45

Things Keira spent money on:

1. Clothing

2. Food

3. Other items

Money spent on Clothing = 1/5 of total money

= 1/5 x $45

Money spent on Clothing = $9

Money spent on Other Items = 1/9 of total money

= 1/9 x $45

Money spent on Other Items = $5

Money spent of on Food = Money spent - (Money spent on clothing + other items)

Money spent on food = 45 - (9+5)

= 45 - 14

Money spent on food = $31

4 0
3 years ago
20 points Return to questionItem 4Item 4 20 points Police records in the town of Saratoga show that 13 percent of the drivers st
Sladkaya [172]

Answer:

a) 0.1423

b) 0.2977

c) 0.56

Step-by-step explanation:

For each driver stopped for speeding, there are only two possible outcomes. Either they have invalid licenses, or they do not. The probability of a driver having an invalid license is independent from other drivers. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

13 percent of the drivers stopped for speeding have invalid licenses.

This means that p = 0.13

14 drivers are stopped

This means that n = 14

(a) None will have an invalid license.

This is P(X = 0)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{14,0}.(0.13)^{0}.(0.87)^{14} = 0.1423

(b) Exactly one will have an invalid license.

This is P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{14,1}.(0.13)^{1}.(0.87)^{13} = 0.2977

(c) At least 2 will have invalid licenses.

Either less than 2 have invalid licenses, or at least 2 does. The sum of the probabilities of these events is decimal 1. Mathematically, this is

P(X < 2) + P(X \geq 2) = 1

We want P(X \geq 2)

So

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1) = 0.1423 + 0.2977 = 0.44

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.44 = 0.56

8 0
2 years ago
Just # 16<br><br>idk what it's "counting" by
zysi [14]
For #16, every input by +1 has an output of +7.

9 + 7 = 16
16 + 7 = 23
23 + 7 = 30.....
3 0
3 years ago
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