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3 years ago

Please answer the question in the picture

Mathematics

1 answer:

Schach [20]3 years ago

3 0

Answer:

Step-by-step explanation:

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Please and thank you provide steps: A rectangle has an area of 20 square feet. A similar rectangle has an area of 180 square fee

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smaller/ larger

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divide by 20 on top and bottom

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3 years ago

416 percent as a decimal

lyudmila [28]

Answer:

The answer is 4.16.

416% = 4.16

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3 years ago

What two kinds of exponents are not allowed to be in a polynomial?

Gekata [30.6K]

Answer:

The short answer is that polynomials cannot contain the following: division by a variable, negative exponents, fractional exponents, or radicals.

Step-by-step explanation:

The short answer is that polynomials cannot contain the following: division by a variable, negative exponents, fractional exponents, or radicals.

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2 years ago

Can someone help me with this please please please I want to pass math.

Sav [38]

Answer:

x = 8

Step-by-step explanation:

∠VUD + ∠WUV = 180° {Straight line}

86 + ∠WUV = 180

∠WUV = 180 - 86

∠WUV = 94°

Sum of all angles of triangle = 180°

∠VUW + ∠UWV + ∠WVU = 180

94 + x + 8 + 9x - 2 = 180

10x + 100 = 180

10x = 180 - 100

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8 0

3 years ago

Read 2 more answers

A market research firm supplies manufacturers with estimates of the retail sales of their products from samples of retail stores

KengaRu [80]

Answer:

The 95% confidence interval for the difference of means is (7.67, 16.33).

The estimate is Md = 12.

The standard error is sM_d = 2.176.

Step-by-step explanation:

We have to calculate a 95% confidence interval for the difference between means.

The sample 1 (this year's sales), of size n1=36 has a mean of 53 and a standard deviation of 12.

The sample 2 (last year's sales), of size n2=49 has a mean of 41 and a standard deviation of 6.

The difference between sample means is Md=12.

$M_d=M_1-M_2=53-41=12$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{12^2}{36}+\dfrac{6^2}{49}}\\\\\\s_{M_d}=\sqrt{4+0.735}=\sqrt{4.735}=2.176$

The degrees of freedom are:

$df=n_1+n_2-1=36+49-2=83$

The critical t-value for a 95% confidence interval and 83 degrees of fredom is t=1.989.

The margin of error (MOE) can be calculated as:

$MOE=t \cdot s_{M_d}=1.989 \cdot 2.176=4.328$

Then, the lower and upper bounds of the confidence interval are:

$LL=M_d-t \cdot s_{M_d} = 12-4.328=7.67\\\\UL=M_d+t \cdot s_{M_d} = 12+4.328=16.33$

The 95% confidence interval for the difference of means is (7.67, 16.33).

7 0

2 years ago