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umka2103 [35]
3 years ago
10

Please help me which one is correct please help me fast answer if you can please

Mathematics
2 answers:
Jobisdone [24]3 years ago
3 0

Answer:

C. 2mn and mn^2

Step-by-step explanation:

All of the other options are like terms.

Option A: -x+3x=2x

Option B: 4a+7a=11a

Option D. 3p^2q+(-p^2q)=2p^2q

Option C: These terms are not like terms since 2mn is not squared while mn^2 is squared.

Hence,

the correct option would be C.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

luda_lava [24]3 years ago
3 0

Answer:

The thrid option or 2mn and mn^2

Step-by-step explanation:

Like terms are sets of terms that have the same variables and powers. All these answer choices have the same variables but answer c are not like terms because the second term is raised to the power of 2 and the first is not. Coefficients do not matter for like terms.

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Ganezh [65]
1 gallon of gas = 44 miles
8 0
1 year ago
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Wesly reads 60 pages in 20 minutes if he reads at the same constant rate what equation could represent this as a proportional re
sergey [27]

Answer:

let m be minutes, p be pages

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For every increase of a minute of reading time, pages that Wesly have read will increase by 3


3 0
3 years ago
I WILL MARK BRAINLIEST IN 5 MINUTES!<br> solve this and explain
miskamm [114]

Answer:

no, it's not.

Step-by-step explanation:

300- 284 = 16

284 - 236 = 48

236 - 156 = 80

156 - 44 = 112

for every one the top line goes up, the bottom line changes too, but it's not at a constant rate. it's not constant, therefore it cannot be linear.

the rate of change formula (or slope formula, they're the same thing) is :

y2- y1/ x2 -x1 and to solve it you plug in the points. x is the same a t and y is h

284-300/ 1-0

-16 /1

-16 (this is the rate of change between the first two points)

236- 284/ 2-1

-48/ 1

-48 (rate of change between the second and third points)

since the rate of change isn't constant, it's not possible for it to be a linear relationship.

7 0
3 years ago
Yesterday morning at 8 a.m. the temperature was -14˚F. At noon it was 10 degrees warmer. The temperature increase between noon a
OLEGan [10]
The temperature was -14°F at 8 a.m.

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The tempertaure increase between noon and 4 p.m. was twice the previous increase in temperature, which was 10°F.
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We want to know the temperature at 4 p.m. so we just add it up to the previous result.
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4 0
3 years ago
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What is the constant rate of change ​
GaryK [48]

Answer:

-2

Step-by-step explanation:

up 2 over 1

going up hill

lmk if you have any questions

8 0
2 years ago
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