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2 years ago

The lateral area of a cone is 400 pi cm squared. The radius is 10 cm. Find the slant height to the nearest tenth.

Mathematics

1 answer:

Ilia_Sergeevich [38]2 years ago

8 0

Answer:

Option A. $40\ cm$

Step-by-step explanation:

we know that

The lateral area of a cone is equal to

$LA=\pi rl$

we have

$LA=400\pi \ cm^{2}$

$r=10\ cm$

substitute and solve for l (slant height)

$400\pi=\pi (10)l$

simplify

$400=(10)l$

$l=400/10=40\ cm$

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Answer:

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Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

$\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}$

$\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}$

$\text{The weight of average pumpkin}=5\text{ kg}$

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

$1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}$

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

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