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2 years ago

How do I graph y=6/5x+1

Mathematics

2 answers:

ElenaW [278]2 years ago

7 0

The easiest way to do this is to look up Mathway graphing and it should be the top hit but it will show you how to graph the line simply the equation in to the blank once the page is open.

Troyanec [42]2 years ago

4 0

Use the slope-intercept form to find the slope and y-intercept.

Slope - 0
Y-intercept - 11/5

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What is the rate of change in y per unit change in x for the function 30x+5y=15

ad-work [718]

Step-by-step explanation:

To find the answer you have to put it into y=mx+b format.

This means that it will be 5y=-30x+15

So it will simplify to y=-6x+3

This means that:

If y=2

You substitute then…

2=-6x+3

So x would equal 1/6.

6 0

3 years ago

What is the square root of 112a^2?

marshall27 [118]

That’s ur answer, your welcome

4 0

2 years ago

What is the value of x when f(x)=7? the function or whatever is f (x) =x^3 - 1

pashok25 [27]

Answer:

f ( 7 ) = 342

Step-by-step explanation:

Step 1:

f ( x ) = x³ - 1 Function

Step 2:

f ( 7 ) = 7³ - 1 Input x value

Step 3:

f ( 7 ) = 343 - 1 Exponents

Answer:

f ( 7 ) = 342 Subtract

Hope This Helps :)

4 0

2 years ago

Read 2 more answers

Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of

jarptica [38.1K]

Answer:

The "probability that a given score is less than negative 0.84" is $\\ P(z$ .

Step-by-step explanation:

From the question, we have:

The random variable is normally distributed according to a standard normal distribution, that is, a normal distribution with $\\ \mu = 0$ and $\\ \sigma = 1$ .
We are provided with a z-score of -0.84 or $\\ z = -0.84$ .

Preliminaries

A z-score is a standardized value, i.e., one that we can obtain using the next formula:

$\\ z = \frac{x - \mu}{\sigma}$ [1]

Where

x is the raw value coming from a normal distribution that we want to standardize.
And we already know that $\\ \mu$ and $\\ \sigma$ are the mean and the standard deviation, respectively, of the normal distribution.

A z-score represents the distance from $\\ \mu$ in standard deviations units. When the value for z is negative, it "tells us" that the raw score is below $\\ \mu$ . Conversely, when the z-score is positive, the standardized raw score, x, is above the mean, $\\ \mu$ .

Solving the question

We already know that $\\ z = -0.84$ or that the standardized value for a raw score, x, is below $\\ \mu$ in 0.84 standard deviations.

The values for probabilities of the standard normal distribution are tabulated in the standard normal table, which is available in Statistics books or on the Internet and is generally in cumulative probabilities from negative infinity, - $\\ \infty$ , to the z-score of interest.

Well, to solve the question, we need to consult the standard normal table for $\\ z = -0.84$ . For this:

Find the cumulative standard normal table.
In the first column of the table, use -0.8 as an entry.
Then, using the first row of the table, find -0.04 (which determines the second decimal place for the z-score.)
The intersection of these two numbers "gives us" the cumulative probability for z or $\\ P(z$ .

Therefore, we obtain $\\ P(z$ for this z-score, or a slightly more than 20% (20.045%) for the "probability that a given score is less than negative 0.84".

This represent the area under the standard normal distribution, $\\ N(0,1)$ , at the left of z = -0.84.

To "draw a sketch of the region", we need to draw a normal distribution (symmetrical bell-shaped distribution), with mean that equals 0 at the middle of the distribution, $\\ \mu = 0$ , and a standard deviation that equals 1, $\\ \sigma = 1$ .

Then, divide the abscissas axis (horizontal axis) into equal parts of one standard deviation from the mean to the left (negative z-scores), and from the mean to the right (positive z-scores).

Find the place where z = -0.84 (i.e, below the mean and near to negative one standard deviation, $\\ -\sigma$ , from it). All the area to the left of this value must be shaded because it represents $\\ P(z$ and that is it.

The below graph shows the shaded area (in blue) for $\\ P(z$ for $\\ N(0,1)$ .

7 0

2 years ago

Please help! (question in attachment)

igor_vitrenko [27]

Ayy you got it right thank you very much your

5 0

2 years ago