How do you convert 1.71 kg to cg?
1 answer:
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now, f(0) = 0, and f(-8) is an imaginary value or no real value.
now, f(-10) will also give us an imaginary value
and f(1) = 4
so, doing a first-derivative test on 0, is imaginary to the left and positive on the right, and before and after 1, is positive as well, so f(x) is going up on those intervals.
however, f(0) is 0 and f(1) is higher up, so the absolute maximum will have to be f(1), and we can use f(0) as a minimum, and since it's the only one, the absolute minimum.
the other two, the endpoint of -10 and the critical point of -8, do not yield any values for f(x).
Answer:
41/3
Step-by-step explanation:
given that your waiting time for a bus in the morning is uniformly distributed on [0, 8], whereas waiting time in the evening is uniformly distributed on [0, 10] independent of morning waiting time.
Sum of both waiting times = X+Y
Where X = morning wait time is U(0.8) and
Y = evening wait time is U(0,10)
Since X and Y are independent
Var(x+y) = Var(x)+Var(y)
Var(x) =
Var(Y) =
Var(x+y)