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myrzilka [38]
3 years ago
12

Identify the translation rule on a coordinate plane that verifies that square A(-4, 3), B(-4, 8), C(-9, 3), D(-9, 8) and square

A'(-3, 2), B'(-3, 7), C'(-8, 2), D'(-8, 7) are congruent.
Mathematics
2 answers:
V125BC [204]3 years ago
6 0
(x+1, y-1)

Because if you look at the corresponding points 1 is added to the x-value of the original point and 1 is subtracted from the y-value of the original point
s2008m [1.1K]3 years ago
4 0

Answer:  The translation rule that verifies that square A(-4, 3), B(-4, 8), C(-9, 3), D(-9, 8) and square A'(-3, 2), B'(-3, 7), C'(-8, 2), D'(-8, 7) are congruent is

(x, y)  ⇒ (x+1, y-1).

Step-by-step explanation:  We are given to identify the translation rule on a coordinate plane that verifies that

square A(-4, 3), B(-4, 8), C(-9, 3), D(-9, 8) and square A'(-3, 2), B'(-3, 7), C'(-8, 2), D'(-8, 7) are congruent.

We see that the co-ordinates of the vertices of square ABCD and A'B'C'D' are related as follows :

A(-4, 3)  ⇒  A'(-4+1, 3-1) = A'(-3, 2),

B(-4, 8)  ⇒  B'(-4+1, 8-1) = B'(-3, 7),

C(-9, 3)  ⇒  C'(-9+1, 3-1) = C'(-8, 2),

D(-9, 8)  ⇒  D'(-9+1, 8-1) = C'(-8, 7).

Therefore, the required translation rule is given by

(x, y)  ⇒ (x+1, y-1).

Thus, the translation rule that verifies that square A(-4, 3), B(-4, 8), C(-9, 3), D(-9, 8) and square A'(-3, 2), B'(-3, 7), C'(-8, 2), D'(-8, 7) are congruent is

(x, y)  ⇒ (x+1, y-1).

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