Answer:
B. 200 doses
Step-by-step explanation:
Given,
1 dose is required for 100 mg,
Since, 1 mg = 0.001 g,
⇒ 100 mg = 0.1 g
⇒ 1 dost is required for 0.1 g,
Thus, the ratio of doses and quantity ( in gram ) is ![\frac{1}{0.1}=10](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B0.1%7D%3D10)
Let x be the doses required for 20 grams,
So, the ratio of doses and quantity is ![\frac{x}{20}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B20%7D)
![\implies \frac{x}{20}=10](https://tex.z-dn.net/?f=%5Cimplies%20%5Cfrac%7Bx%7D%7B20%7D%3D10)
![\implies x=200](https://tex.z-dn.net/?f=%5Cimplies%20x%3D200)
Hence, 200 doses can be obtained from 20 grams of the drug.
Option 'B' is correct.
That would be written as:
![z^{2} = 1](https://tex.z-dn.net/?f=z%5E%7B2%7D%20%3D%201)
And the step-by-step equation would be:
→ we take the 2 to the right side of the equation and do the IO*
→we solve for ![\sqrt{1}](https://tex.z-dn.net/?f=%5Csqrt%7B1%7D)
→ final answer
*Ps - IO is not an existing term and stands for inverse operation. In this case, because when we take to 2 to the right side of the equation (the 2 is a power) it'll have to turn into a square root (because exponents and roots are inverse operations)
Hope it helped,
BioTeacher101
78 = 2 x 3 x 13
1 x 78
2 x 39 = 78
3 x 26=78
6 x 13 = 78
larger number is 13
<h3>Given</h3>
... r + 7 = 9
<h3>Find</h3>
... r
<h3>Solution</h3>
Subtract 7 from both sides of the equation.
... r + 7 - 7 = 9 - 7
... r = 2 . . . . . . simplify
Expressed as a solution set, this may look like ...
... r ∈ {2}
_____
You probably had no trouble solving this in 2nd grade when it was shown to you in the form ...
__ + 7 = 9