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Usimov [2.4K]
2 years ago
7

Help please and thank you.

Mathematics
1 answer:
devlian [24]2 years ago
5 0

Answer:

1.66667

Step-by-step explanation:

4 x ? = 12    ? = <u>3</u>

so,

z x ? = 5  

5/<u>3</u> = 1.6666667

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Joanne was hired by a florist to make large boes for holidays wreaths each roll of ribbon has 20 yards joanne used 3 1/2 rolls o
alukav5142 [94]

Answer: Each bow needs 4.67 yards of ribbon.

Step-by-step explanation:

We know that each roll has 20 yd.

She used 3 + 1/2 rolls, then the total length used will be (3 + 1/2) times the length of each roll, this is:

(3 + 1/2)*20 yd = (6/2 + 1/2)*20yd = (7/2)*20yd = 70 yd.

With tose 70 yards of ribbon, she made 15 bows, then the length of ribbon used in each bow will be equal to the quotient between the total length used and the number of ribbons made with it, this is:

70yd/15 = 4.67 yards

Each bow needs 4.67 yards of ribbon.

6 0
2 years ago
What is the measure of angle k?
Murljashka [212]

9514 1404 393

Answer:

  59°

Step-by-step explanation:

Opposite angles of an inscribed quadrilateral are supplementary.

  ∠N +∠L = 180°

  (a +16) +(a -18) = 180

  2a = 182 . . . . . . . . . . add 2

  a = 91 . . . . . . . . . . . . divide by 2

Then the measure of angle M is ...

  ∠M = (a+30)° = (91 +30)° = 121°

and angle K is its supplement.

  ∠K = 180° -121°

  ∠K = 59°

8 0
2 years ago
find the slope intercept form of the equation of the the line that passes through (-9,-8) and the origin
Debora [2.8K]

Answer:

The answer is y=8/9x

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The radius of a circle is 2.8 cm. Find the circumference to the nearest tenth.
Neporo4naja [7]

Answer: 17.59 cm

Step-by-step explanation: C=2πr=2·π·2.8=17.59292 cm

6 0
2 years ago
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The heights of a random sample of 100 women are recorded. The sample mean is 65.3 inches and the sample standard deviation is 3
Keith_Richards [23]

Answer: B. 65.3\pm(2)(0.3)

Step-by-step explanation:

The confidence interval for the population mean is given by :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

Given : Sample size : n= 100

Sample mean : \overline{x}=65.3\text{ inches}

Standard deviation: \sigma=3 \text{ inches}

Level of confidence = 0.95

Significance level : \alpha=1-0.95=0.05

Critical value : z_{\alpha/2}=1.96

Then, 95% confidence interval for the population mean will be :-

65.3\pm (1.96)\dfrac{3}{\sqrt{100}}\\\\\approx65.3\pm(2)(\dfrac{3}{10})=65.3\pm(2)(0.3)

8 0
2 years ago
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