Answer:
Heights of 29.5 and below could be a problem.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.
This means that ![\mu = 32, \sigma = 1.5](https://tex.z-dn.net/?f=%5Cmu%20%3D%2032%2C%20%5Csigma%20%3D%201.5)
There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.
Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus
![X - 32 = -1.645*1.5](https://tex.z-dn.net/?f=X%20-%2032%20%3D%20-1.645%2A1.5)
![X = 29.5](https://tex.z-dn.net/?f=X%20%3D%2029.5)
Heights of 29.5 and below could be a problem.
Answer:
Hi the answer is A, hopefully i helped you
Answer:
-5 If it is one of your answers it will be -5
Step-by-step explanation:
If you take 10 and have 3 decrease every minute and did it for 5 minutes it will go 10 7 4 1 -2 -5 That is 5 minutes of the temperature decreasing by 3 I hope it is right.
Answer:
yes
Step-by-step explanation: