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aniked [119]
3 years ago
15

An executive committee consists of 1313 ​members: 55 men and 88 women. 44 members are selected at random to attend a meeting in

hawaii. the names are drawn from a hat. what is the probability that all 44 selected are womenwomen​?
Mathematics
1 answer:
galben [10]3 years ago
8 0

It is given in the question that

An executive committee consists of 13 ​members: 5 men and 8 women. 4 members are selected at random to attend a meeting in hawaii. the names are drawn from a hat.

And we have find the probability of selecting all 4 women.

Selecting 4 women out of 8 women is

8C4= 70

Selecting 4 from a total of 13 persons

13C4=715

Required probability

= \frac{70}{715} = \frac{14}{143}

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First, we can say that ∠ACB and ∠BCF are opposite angles because they are not next to each other and are formed by intersecting lines. Therefore, ∠ACB = ∠BCF

Next, angles correspond with the side opposite of it. This means that, for example, ∠ACB corresponds with line AB and ∠BCF corresponds with line BF. Because ∠ACB and ∠BCF are equal and the triangles are similar, we can say that their corresponding sides have a ratio with each other. Similarly, ∠CAB corresponds to CB, ∠ABC corresponds to AC, ∠CWV corresponds to CV, and ∠CVW corresponds to CB.

Because the triangle CVW is isosceles, we can say that the angles whose corresponding sides are equal are equal as well, so ∠CAB = ∠ABC and ∠CVW = ∠CVW. Next, because ∠ACB and ∠BCF are equal and correspond to each other, and the other two angles in each triangle are equal to each other, we can say that the other two angles must be equal. Another way of putting this is like this:

Say that x = ∠CAB. Then,

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Filling in the blank, 84/182 is equal to 84/182, so ? = 182

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