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LekaFEV [45]
3 years ago
10

Whats the volume of the pyramid shown

Mathematics
1 answer:
adell [148]3 years ago
7 0

Answer:

Volume of the Pyramid = 40 cubic centimeters

Step-by-step explanation:

The volume of a pyramid is given by the formula:

V=\frac{lwh}{3}

Where

l is the length

w is the width

h is the height

In the figure shown, the length is 5, width is 4, and height is 6 (in cm). We just substitute and find the answer. Shown below:

V=\frac{lwh}{3}\\V=\frac{5*4*6}{3}\\V=40

So, we can say:

Volume of the Pyramid = 40 cubic centimeters

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a) r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857  

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Step-by-step explanation:

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The correlation coeffcient is given by this formula:

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n=4 \sum x = 200, \sum y = 5.37, \sum xy = 333, \sum x^2 =12000, \sum y^2 =9.3501  

r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857  

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

Part b

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

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S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=12000-\frac{200^2}{4}=2000  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=333-\frac{200*5.37}{4}=64.5  

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m=\frac{64.5}{2000}=0.03225  

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