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wariber [46]
3 years ago
8

What is the unit price for the cans of lemonade at each of the stores?

Mathematics
2 answers:
zvonat [6]3 years ago
4 0
For shop smart, the price is 48 packs for 9 dollars so you would divide
9 ÷ 48 to find the price for dollars per can which is 19 cents per can
for super save it's saying 48 packs for 10 dollars so divide
10 ÷ 48 and that is 21 cents per can
for price buster it's saying 36 packs for 9 dollars so you would divide
9 ÷ 36 which is 25 cents per can
so Mei Pilar and David should purchase the cans at shop smart since it's cheaper
Nonamiya [84]3 years ago
3 0

Answer:

Mié, Pillar and David should buy the lemonades from shop smart store.

Step-by-step explanation:

At shop smart store, we have:

24 packs (2 for 9):

\frac{9}{2}=4.5 per pack

\frac{4.5}{24}=0.1875 or approx 19 cents per can.

At super save store, we have :

12 packs (4 for 10):

\frac{10}{4}=2.5 per pack

\frac{2.5}{12}=0.208 or approx 21 cents per can.

At price busters store, we have:

12 packs (3 for 9):

\frac{9}{3}=3 per pack

\frac{3}{12}=0.25 equals 25 cents per can.

Now, comparing the three values, we can see that 19 cents per can is the cheapest.

So, Mié, Pillar and David should buy the lemonades from shop smart store.

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Which of the following statements represents one of the differences between an experiment and an observational study?
svet-max [94.6K]

Answer:

Introducing a change to the subgroup

Step-by-step explanation:

Given there are four statements.  We have to find the one which represents one of the differences between an experiment and an observational study.

The answer is option 2. Introducing a change to the subgroup

Experimental and observational studies are both types of studies between which a number of differences can be identified. When conducting research studies,  various types of research in order to arrive are adopted according to the need.  

An experimental study is a study where the researcher has control over most of the variables.

On the other hand, an observation study is a study where the researcher cannot control any variable but merely observes the subject without controlling any variables.

3 0
3 years ago
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Alice searches for her term paper in her filing cabinet, which has several drawers. She knows thatshe left her term paper in dra
katen-ka-za [31]

You made a mistake with the probability p_{j}, which should be p_{i} in the last expression, so to be clear I will state the expression again.

So we want to solve the following:

Conditioned on this event, show that the probability that her paper is in drawer j, is given by:

(1) \frac{p_{j} }{1-d_{i}p_{i}  } , if j \neq i, and

(2) \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i}  } , if j = i.

so we can say:

A is the event that you search drawer i and find nothing,

B is the event that you search drawer i and find the paper,

C_{k}  is the event that the paper is in drawer k, k = 1, ..., n.

this gives us:

P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}

P(A) = 1 - P(B) = 1 - d_{i} p_{i}

Solution to Part (1):

if j \neq i, then P(A \cap C_{j} ) = P(C_{j} ),

this means that

P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)}  = \frac{P(C_{j} )}{P(A)}  = \frac{p_{j} }{1-d_{i}p_{i}  }

as needed so part one is solved.

Solution to Part(2):

so we have now that if j = i, we get that:

P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}

remember that:

P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}

this implies that:

P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )

so we just need to combine the above relations to get:

P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i}  }

as needed so part two is solved.

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3 years ago
Water costs $1.25 per bottle. At this rate, what is the cost of 10 bottles?
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The answer is $12.5 for 10 bottles
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A maxm speed of 55 mph means that the speed has to be lexx than or equal to 55

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I will give brainliest <br> Find n. <br> 35n/35 = 700/35
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Answer:

20

Step-by-step explanation:

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35*\frac{35n}{35} = 700 * 35\\35n = 700

divide both sides by 35

n = 20

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3 years ago
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