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QveST [7]
3 years ago
8

GET 11 POINTS AND A THANKS AND BE NAMED BRAINIEST

Mathematics
1 answer:
babunello [35]3 years ago
3 0

Answer:

B. Tire barn 20% rebate Cory will save $36

Step-by-step explanation:

If you take 20% off of $180 you are left with 144 dollars. This means that $36 was taken off.

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(5a-5)(2a+2)<br> Find each product
weeeeeb [17]
(<span>5a-5)(2a+2)
= 5a*2a -5*2a + 2*5a - 5*2
= 10a^2  - 10a + 10a  - 10
= 10a^2 - 10


The product of the equation is </span>10a^2 - 10
6 0
3 years ago
Read 2 more answers
Helpppppp mathhhhhhhhh
creativ13 [48]
I hope this helps you




cos71=15/P



0.325=15/P



P=46.15
8 0
4 years ago
Suppose a tub has the shape of an elliptical paraboloid given by z = ax2+by2 (where a, b are some positive constants). If a marb
Umnica [9.8K]

Answer:

It would roll in this direction.

\nu  =  (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})

Step-by-step explanation:

It would roll to the direction of maximum decrease, which is the -1 times the direction of maximum increase, which is given by the gradient of the function.  

Since  

z =  ax^2  + by^2

For this case, the gradient of your function would be

\nabla z  = (2ax , 2by)

And  -1  times the gradient of your function would be

-\nabla z  = (-2ax , -2by)\\

Then, at

 (1,1,a+b),\\x = 1 \\y = 1

So it would go towards

v = (-2a,-2b)

The magnitud of that vector is

|v| =  2\sqrt{a^2+b^2}

and to conclude it would roll in this direction.

\nu  =  (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})

6 0
3 years ago
The radius of a circle is 11 feet. What is the circle's area? Use 3.14 for ​
vovikov84 [41]

Answer:

Formula for area of a circle;

<u>A = πr^2</u>

where pi is 3.14 in this case, and r is the radius squared

Plug in the actual values;

A = 3.14 x 11^2

A = 3.14 x 121

A = 379.94 square feet

7 0
2 years ago
Solve 5kx + 6 = 7kx for x.<br> А. x=3/k<br> в. х = -2/k<br> с. x =-3/k<br> D. x=2/k
slamgirl [31]

Answer:

A.  x = 3/k.

Step-by-step explanation:

5kx + 6 = 7kx

5kx - 5kx + 6 = 7kx - 5kx

6 = 2kx

x = 6 / 2k

x = 3/k.

7 0
3 years ago
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