Answer:
0.053246
Step-by-step explanation:
log(26)−log(23)
=1.414973−log(23)
=1.414973−1.361728
=0.053246
Answer:
0.7777..... is 7/9
Step-by-step explanation:
use the calculator to solve this q
Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
A because radius is half of the diameter
a. The gradient is
b. The gradient at point P(1, 2) is
c. The derivative of 
at P in the direction of 
is
It looks like
so that
Then
