Answer:
Solar flux that incident on it is given as
S = 160 W/m/m
Now we know that the area of solar panels is given as
A = 10 m^2
So total solar power received by solar panels is given as
Power Received = (Solar flux) \times (Area)PowerReceived=(Solarflux)×(Area)
P = S\times AP=S×A
now here we have
P = 160 \times 10P=160×10
P = 1600 WP=1600W
now we know that efficiency of the solar panels is 20%
so total output power will be
efficiency = \frac{P_{out}}{P_{in}}efficiency=
P
in
P
out
0.20 = \frac{P_{out}}{1600}0.20=
1600
P
out
P_{out} = 320 WP
out
=320W
Answer:
Explanation:
Given
Required
Determine the Net Primary Productivity (NPP)
NPP is calculated as follows;
Substitute values for GPP and R
<em>Hence, the Net Primary Productivity is </em>
<em></em>
He is a prophet, and a messanger of god.
