ΔABC is a 45 - 45 - 90 triangle. The pattern of its sides is as follows:
Each leg = 1 unit (and both legs are that way, since the triangle is isosceles - so two sides are the same)
Hypotenuse = √2 units.
So if we know either leg, we multiply by √2 to get the hypotenuse. In reverse, we divide by √2 if we know the hypotenuse to get the measurement of a leg.
Our problem tells us that the hypotenuse AC is 10 units. We divide 10 by √2 to get the measurement of leg AB. Since it's a 45 -45 - 90 triangle, AB = BC.
to rationalize the radical
Thus, each leg is 5\sqrt{2} [/tex].
For 8 rooks
Without conflict (i.e. there is no row or column can contains 2 rooks)
then there are 8 choices for the first one in the first column, 7 choices in the second, ...1 choice in the last (eighth) column for a total of
8!=40320 ways.
Unlimited conflicts
there are 64 choices for the first, 63 for the second, .... 57 for the last, for a total of 64!/56!=178462987637760 ways
Similarly, for n rooks, with unlimited conflicts, there are
64!/(64-n)! ways
The Answer is y=2x+3 Because<span>
y = 3x + 1
2x + 3 = 3x + 1
2 = x and y = 7 || ordered pair(2,7) is the solution for this syetem</span>
