Answer:
yes
Step-by-step explanation:
not sure how to explain it's kinda hard sorry
4 packs of notepads and 5 packs of sticky notes
Explanation: if he needs the same number of both he needs to find the first number that 4 and 5 both go into. 4 x 5 = 20 so this is the least common multiple
According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7
Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.
Given,
n = 66
We know that,
According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:

Here, n is equal to 66 and by substituting the value to the equation we get:

k = 7.0444
k ≈ 7
Learn more about Sturge's rule here: brainly.com/question/28184369
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B+ p= 10.40
b=2x 2.50
Now using substitution method replace b in first equation with value of second equation basically combing the two equations into one do you end up with one variable to solve .
2 x 2.50 +p =10.40
5 + p=10.40
P=$5.40
b =$5.00
The answer is EACH pendant cost $2.70
(You have to divide 5.40 by two )