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alexdok [17]
3 years ago
13

The side of a triangles are 8cm,12cm,17cm.find its perimeter and its are by using herons formula

Mathematics
2 answers:
Novay_Z [31]3 years ago
5 0

Answer:

see explanation

Step-by-step explanation:

The perimeter is the sum of the 3 sides, that is

perimeter = 8 + 12 + 17 = 37 cm

To use Heron's formula for area (A)

A = \sqrt{s(s-a)(s-b)(s-c)}

where a, b and c are the lengths of sides and s the semi perimeter

s = 37 ÷ 2 = 18.5

let a = 8, b = 12 and c = 17, then

A = \sqrt{18.5(18.5-8)(18.5-12)(18.5-17)}

   = \sqrt{18.5(10.5)(6.5)(1.5)}

   = \sqrt{1893.9375} ≈ 43.52 cm² ( to 2 dec. places )

igor_vitrenko [27]3 years ago
3 0

Hi!

Heron's formula:

s = \dfrac{a+b+c}{2}

Area = \sqrt{s(s-a)(s-b)(s-c)}

Perimeter = 8 + 12 + 17 = 37 cm

s = \dfrac{37}{2} = 18.5

Area = \sqrt{18.5(18.5-8)(18.5-12)(18.5-17)} = \sqrt{18.5 * 10.5 * 6.5 * 1.5} = \sqrt{1893,9375}

[tex]\sqrt{1893.9375} ≈ 43.52

Area ≈ 43.52 cm²

Wish Good Lessons! ^-^

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Answer:

The largest integer value that makes the inequality true is 9.

General Formulas and Concepts:
<u>Algebra I</u>

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

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<u>Step 2: Solve for </u><u><em>x</em></u>

  1. Simplify:                                                                                                            x - 8 < 2x + 1
  2. [Subtraction Property of Equality] Subtract <em>x</em> on both sides:                        -8 < x + 1
  3. [Subtraction Property of Equality] Subtract 1 on both sides:                        -8 < x
  4. Rewrite:                                                                                                           x > -8

∴ we see that any number <em>x greater than -8</em> would work as a solution to the inequality. That would mean the next largest integer, 9, would be our answer.

---

Topic: Algebra I

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