Answer:
1 x 10^13 stadiums will be needed in this scenario
Explanation:
We are told that
1 stadium holds = 1 × 10^5 people and
Number of iron atoms = 1 × 10^18 atoms
If the stadium carries an equivalent number of atoms as that of people.
We can infer that 1 stadium will carry 1 × 10^5 atoms.
The calculation to determine the number of stadiums would then be 1 × 10^18 divided by 10^5 atoms/stadium which was gotten by dividing the total number of atoms by the number of atoms per stadium.
Number of stadiums = Total number of atoms ÷ Number of atoms per stadium
= 1 × 10^18 atoms ÷ 1 × 10^5 atoms/stadium
= 1 × 10^13 Stadiums
This means that 1 × 10^18 atoms would occupy 1 × 10^13 stadiums
Can you include the following substitutions??
38*10^(-4)=0.0038
This means you move the decimal to the left (divided by 10) four times.
4.0*10^(-2)=0.04
This means you move the decimal to the left two times. Now add the two.
0.0038+0.04
Always line up decimals when adding them!
The final answer is 0.0438
Answer:
<h2>
3/16</h2>
Explanation:
Given:
Long eyelashes (L) are dominant to short eyelashes(l), So L is dominant on l.
Wet ear wax (W) is dominant dry ear wax (w) , so W is dominant on w.
Two heterozygous parents are...
LlWw and LlWw
F1 generation
3 child have long eyelashes and dry wax = L_ww .
There is 3/16 ( 3 out of 16) chances that the child have long eyelashes and dry ear wax and their genotype is L_ww.
