10*10-2*3/2-4*3/2-2*3/2-2*3/2-5*2-6*2/2-5*2-3*2/2
100-3-6-3-3-10-6-10-3
100-15-29
100-44
56
Answer:
es kunno.............................
It is <span>A.
Dear Mrs. Khouri, u always cap dear and her place is a ms so thats cap,and u always cap someones name
</span>
Answer:
a. 6% one is better
b. $12,285.95
Step-by-step explanation:
a. For determining which investment earn more first we have to calculate both the investment which are as follows
a. Based on compound quarterly, the amount is find out by using the following formula
![Amount = {Present\ value\times (1 + interest\ rate)} ^{number\ of\ years}](https://tex.z-dn.net/?f=Amount%20%3D%20%7BPresent%5C%20value%5Ctimes%20%281%20%2B%20interest%5C%20rate%29%7D%20%5E%7Bnumber%5C%20of%5C%20years%7D)
where,
Present value is $50,000
Interest rate is =
= 0.015
And, the number of years is
= ![4\times4](https://tex.z-dn.net/?f=4%5Ctimes4)
= 16
So, the amount is
![= \$50,000 \times (1 + 0.015)^{16}](https://tex.z-dn.net/?f=%3D%20%5C%2450%2C000%20%5Ctimes%20%281%20%2B%200.015%29%5E%7B16%7D)
= $63,449.28
And, based on compounded continuously, the amount is determined by using the following formula
![Amount = Present\ value\times e^{rt}](https://tex.z-dn.net/?f=Amount%20%3D%20Present%5C%20value%5Ctimes%20e%5E%7Brt%7D)
![= \$50,000 \times e.^{0575(4)}](https://tex.z-dn.net/?f=%3D%20%5C%2450%2C000%20%5Ctimes%20e.%5E%7B0575%284%29%7D)
= $51,163.33
Therefore, The the investment at 6% is better
b. Now the difference in earning is
= $63,449.28 - $51,163.33
= $12,285.95
We are given with the best fit line
<span>y = 2,500x - 2,500
The y-intercept is -2500
and the slope is 2500
This line can be translated into the following statements:
At the start of the operations, there is a negative profit of -2500. Each year, the profit increases by 2500</span><span />