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Setler [38]
3 years ago
7

How many neoutrons does sulenium 82have?

Chemistry
1 answer:
likoan [24]3 years ago
6 0
45 number of neutrons
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1. Which of the following facts did Dalton realize?
Ne4ueva [31]
He discovered choice C! this is because atoms of the same element can have different numbers of neutrons
8 0
2 years ago
Would an element with 7 valence electrons be more or less reactive than an element with 3 valence electrons?
Sedbober [7]

Answer:

That would be more

Explanation:

5 0
3 years ago
if a saline bag has a molarity of 0.155 and 0.75 L are given to a patient how many grams of NaCl did the patient receive?
katrin [286]

Answer:

Mass = 6.79 g

Explanation:

Molarity = 0.155

Volume = 0.75L

Mass = ?

The relationship between these quantities is given as;

Molarity = Number of moles / Volume

Number of moles = Volume * Molarity

Number of moles = 0.75 * 0.155 = 0.11625 moles

Number of moles = Mass / Molar mass

Mass = Molar mass * Number of moles

Mass = 58.44277 g/mol * 0.11625 mol

Mass = 6.79 g

8 0
2 years ago
Two different proteins X and Y are dissolved in aqueous solution at 37 °C. The proteins bind in a 1:1 ratio to form XY. A soluti
aleksklad [387]

Answer:

Kc of reaction is 20.

Explanation:

The two proteins are X and Y.

The [X] = 1mM

[Y]=1mM

At equilibrium, [X] = 0.2mM  [Y] = 0.2mM

we know that equilibrium constant is:

Kc=\frac{[Products]}{[Reactants]}=\frac{[XY]}{[X][Y]}

[XY]= 1-0.20=0.80 mM

putting values:

Kc=\frac{0.80}{0.20X0.20}=20

8 0
3 years ago
To break the oxygen-oxygen bonds in a single O2 molecule, 1 × 10–18 J of energy is required. Which of the following wavelengths
Sonbull [250]

E = hc/(lamda)

The lamda symbol is wavelength, which this site does not have. I can represent it with an "x" instead.

Plancks constant, h = 6.626×10^-32 J·s

Speed of light, c = 3.00×10^8 m/s

The energy must be greater than or equal to 1×10^-18 J

1×10^-18 J ≤ (6.626×10^-32 J·s)*(3.0×10^8 m/s) / x

x ≤ (6.626×10^-32 J·s)*(3.0×10^8 m/s) / (1×10^-18 J)

x ≤ 1.99×10^-7 m or 199 nm

The wavelength of light must be greater than or equal to 199 nm

8 0
3 years ago
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