Answer:
Concentration of nitrate in the new solution = 0.007 M
Explanation:
Given:
Concentration nitrate solution = 0.070 m
Volume of aliquote of the nitrate solution is add = 10.0 ml
Total volume = 100 ml
Find:
Concentration of nitrate in the new solution
Computation:
Number of M. mole = 0.070 m x 10.0 ml
Number of M. mole = 0.7 m-moles
Concentration of nitrate in the new solution = 0.7 m-moles / 100 ml
Concentration of nitrate in the new solution = 0.007 M
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Answer:
Explanation:
(a) Balanced equation
2Zn + O₂ ⟶ 2ZnO
(b). Calculation
You want to convert moles of ZnO to moles of Zn
The molar ratio is 2 mol Zn:2 mol ZnO
Explanation:
Rate = 84mL/s
A minute has 60 seconds;
Rate = 84mL/s * 60s = 5040 mL/minute
Volume of blood in a minute = Rate * Number of beeats per minute
Volume = 5040 * 72 = 362880 mL
How long to circulate 3500ml?
1 minute = 362880mL
x = 3500 mL
x = 3500mL min / 362880mL
Math Expression:
Time to circulate 3500ml of blood (min) = 3500ml * 1 minute / Volume of blood at a rate of 84ml/s and 72 beats per minute (ml)
To make sure that an equation is balanced, we need to have the same number of atoms on both sides. If we had only 2(I₄O₉) on one side, then the other side would need to have 8 iodine atoms and 18 oxygen atoms to obey the law of conservation of mass. This can be found by multiplying the coefficient to the subscript followed by the element symbol.
Your correct answer is 8 iodine atoms and 18 oxygen atoms.
