All categories

2 years ago

A summer camp has 110 dividend as evenly as possible into 9 cabins.About how many campers are in each cabin?

Mathematics

1 answer:

enot [183]2 years ago

8 0

Answer:

Step-by-step explanation:

divide 110 by 9 and the answer is 12.2, since 2 is below 5 you round back to the nearest whole number and you'll receive 12.

You might be interested in

Can anyone help!?! I don’t understand the distance formula. Can someone pls explain it?

Jobisdone [24]

Explain what? ........

5 0

3 years ago

HELP HELP HELP , I WILL MARK BRAINLIEST!!

Nataly [62]

Answer:

Step-by-step explanation:

3 0

2 years ago

If y = x3 - 3 , find the value of y when x = -2

Contact [7]

Y = (-2)3 - 3
Y = -6 - 3
Y= -9

8 0

2 years ago

A rectangular prism has a length of 18 meters, a height of 19 meters, and a width of 11 meters. What is its volume, in cubic met

victus00 [196]

3762 cubic meters.
Explanation: Just multiply the length by the width and then that product by the height. The rider doesn’t really matter just multiply the three values.

5 0

3 years ago

Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week. A sample of

prohojiy [21]

Answer:

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical value would be $t_{\alpha/2}=1.669$

And replacing we got

$17.5-1.669\frac{4.2}{\sqrt{65}}=16.63$

$17.5+1.669\frac{4.2}{\sqrt{65}}=18.37$

For the 95% confidence the critical value is $t_{\alpha/2}=1.998$

$17.5-1.998\frac{4.2}{\sqrt{65}}=16.46$

$17.5+1.998\frac{4.2}{\sqrt{65}}=18.54$

Step-by-step explanation:

Information given

$\bar X¿ 17.5$ represent the sample mean

$\mu$ population mean (variable of interest)

s¿4.2 represent the sample standard deviation

n¿65 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=65-1=64$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical value would be $t_{\alpha/2}=1.669$

And replacing we got

$17.5-1.669\frac{4.2}{\sqrt{65}}=16.63$

$17.5+1.669\frac{4.2}{\sqrt{65}}=18.37$

For the 95% confidence the critical value is $t_{\alpha/2}=1.998$

$17.5-1.998\frac{4.2}{\sqrt{65}}=16.46$

$17.5+1.998\frac{4.2}{\sqrt{65}}=18.54$

8 0

3 years ago