Answer:
MARK me brainliest please and follow my page
Explanation:
All you have to do to get the average speed is to calculate the total distance covered and divide it by the total time taken
= 16/18 = 0.88m/s
Answer:
Orbital period of satellite is 5.83 x 10³ s
Explanation:
The orbital period of satellite revolving around Earth is given by the equation :
.....(1)
Here R is radius of Earth, h is height of satellite from the Earth's surface, M is mass of Earth and G is gravitational constant.
In this problem,
Height of satellite, h = 500 km = 500 x 10³ m
Substitute 6378.1 x 10³ m for R, 500 x 10³ m for h, 5.972 x 10²⁴ kg for M and 6.67 x 10⁻¹¹ m³ kg⁻¹ s⁻² for G in equation (1).
![T=\sqrt{\frac{4\pi ^{2} [(6378.1+500)\times10^{3} ]^{3} }{6.67\times10^{-11} \times5.972\times10^{24} } }](https://tex.z-dn.net/?f=T%3D%5Csqrt%7B%5Cfrac%7B4%5Cpi%20%5E%7B2%7D%20%5B%286378.1%2B500%29%5Ctimes10%5E%7B3%7D%20%5D%5E%7B3%7D%20%7D%7B6.67%5Ctimes10%5E%7B-11%7D%20%5Ctimes5.972%5Ctimes10%5E%7B24%7D%20%7D%20%7D)
<em>T</em> = 5.83 x 10³ s
Answer:
A. False
B. False
C. True
D. True
E. True
F. True
Explanation:
A. The equation Ax=b is referred to as a matrix equation and not vector equation.
B. If the augmented matrix [ A b ] has a pivot position in every row then equation Ax=b may or may not be consistent. It is inconsistent if [A b] has a pivot in the last column b and it is consistent if the matrix A has a pivot in every row.
C. In the product of Ax also called the dot product the first entry is a sum of products. For example the the product of Ax where A has [a11 a12 a13] in the first entry of each column and the corresponding entries in x are [x1 x2 x3] then the first entry in the product is the sum of products i.e. a11x1 + a12x2 +a13x3
D. If the columns of mxn matrix A span R^m, this states that every possible vector b in R^m is a linear combination of the columns which makes the equation consistent. So the equation Ax=b has at least one solution for each b in R^m.
E. It is stated that a vector equation x1a1 + x2a2 + x3a3 + ... + xnan = b has the same solution set as that of the linear system with augmented matrix [a1 a2 ... an b]. So the solution set of linear system whose augmented matrix is [a1 a2 a3 b] is the same as solution set of Ax=b if A=[a1 a2 a3] and b can be produced by linear combination of a1 a2 a3 iff the solution of linear system corresponding to [a1 a2 a3 b] takes place.
F. It is true because lets say b is a vector in R^m which is not in the span of the columns. b cannot be obtained for some x which belongs to R^m as b = Ax. So Ax=b is inconsistent for some b in R^m and has no solution.
