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2 years ago

Answer part (d) please

Physics

2 answers:

attashe74 [19]2 years ago

7 0

Average speed = (distance covered) / (time to cover the distance)

For the full 18 seconds described by the graph . . .

Average speed = (16 meters) / (18 seconds)

Average speed = (16 / 18) m/s

Average speed = 0.89 m/s

finlep [7]2 years ago

3 0

Answer:

MARK me brainliest please and follow my page

Explanation:

All you have to do to get the average speed is to calculate the total distance covered and divide it by the total time taken

= 16/18 = 0.88m/s

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What is the difference between distance and displacement? Give an example of a situation where distance and displacement both ha

Oksana_A [137]

Explanation :

Distance is total path travelled by an object during its entire journey. It is a scalar quantity i.e only magnitude.

Displacement is the shortest distance covered by an object. It is basically the change in position of object. It is a vector quantity i.e direction as well as magnitude.

When an object is travelling in a straight line and stops at the end point, then both distance and displacement are same.

When an object is travelling in a straight line and then changes its direction or we can say come backwards then the magnitude of distance and displacement are different.

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3 years ago

Current that moves in one direction from negative to positive. May be created by a battery. Is generally NOT found in U.S. elect

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That's "DC" . . . Direct Current .

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2 years ago

Read 2 more answers

A single-phase electrical load draws 600KVA at 0.6 power factor lagging. a) Find the real and reactive power absorbed by the loa

Whitepunk [10]

Answer:

(a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

Explanation:

Given that,

Power factor = 0.6

Power = 600 kVA

(a). We need to calculate the reactive power

Using formula of reactive power

$Q=P\tan\phi$ ...(I)

We need to calculate the $\phi$

Using formula of $\phi$

$\phi=\cos^{-1}(Power\ factor)$

Put the value into the formula

$\phi=\cos^{-1}(0.6)$

$\phi=53.13^{\circ}$

Put the value of Φ in equation (I)

$Q=600\tan(53.13)$

$Q=799.99\ kVAR$

(b). We draw the power triangle

(c). We need to calculate the reactive power of a capacitor to be connected across the load to raise the power factor to 0.95

Using formula of reactive power

$Q'=600\tan(0.95)$

$Q'=9.94\ KVAR$

We need to calculate the difference between Q and Q'

$Q''=Q-Q'$

Put the value into the formula

$Q''=799.99-9.94$

$Q''=790.05\ KVAR$

Hence, (a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

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3 years ago

How long will it take to go 150,000 m traveling at 50 km/hr

Vanyuwa [196]

150 km / 50 km/h = 3h

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2 years ago

Read 2 more answers

A particle moves along the x axis according to the equation x = 6t², where x is in meters and t is in seconds. Therefore:

vladimir2022 [97]

Answer is E

time can be negative.
A is not true because a=d2xdt2=12 m/s2
C: question already said that particle move along x-axis, which is not parabola path.
D: velocity is dxdt=12t, therefore velocity changes by 12 m/s and not 9.8 m/s
So we are left with E.

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3 years ago