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STALIN [3.7K]
2 years ago
12

Part A Every force has one and only one 3rd law pair force. Every force has one and only one 3rd law pair force. true false Requ

est Answer Part B The two forces in each pair act in opposite directions. The two forces in each pair act in opposite directions. true false Request Answer Part C The two forces in each pair can either both act on the same body or they can act on different bodies. The two forces in each pair can either both act on the same body or they can act on different bodies. true false
Physics
1 answer:
Scorpion4ik [409]2 years ago
4 0

Answer:

Explanation:

Part A

Every force has one and only  pair force , according to 3 rd law

It is true , the pair force has equal magnitude .

Part B

The two forces in each pair act in opposite directions.

It is true .

The pair forces are equal and act in opposite direction .

Part C

The two forces in each pair can either both act on the same body or they can act on different bodies.

It is false .

The two forces in each pair can not act on same body  . They act on different bodies , bodies which are undergoing mutual interaction.

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vector ????⃗ has a magnitude of 17.9 and its direction is 80∘ counter‑clockwise from the x- axis. what are the x- and y- compone
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We have vector (17.9*cos80^{0},17.9*sin80^{0})

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<h3>What is a vector?</h3>

An object with both magnitude and direction is referred to be a vector. A vector can be visualized geometrically as a directed line segment, with an arrow pointing in the direction and a length equal to the magnitude of the vector. The vector points in a direction from its tail to its head.

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4 0
3 years ago
Pascal has 96 miles remaining to complete his cycling trip. If he reduced his current speed by 4 miles per hour, the remainder o
Verdich [7]

Answer:

V = 20 miles /sec

Explanation:

We have remaining distance   =  d  = 96 miles

Lets call  Pascal velocity  V in miles per hour

Now if he increases his velocity by  50 % (equivalent to multiply by 1.5 ) he will need a time t₁ to arrive then as V = d/t

1.5* V  = d/ t₁      ⇒   1.5 * V  =  96 /t₁

And in the case of reducing his velocity

(V / 4) = d/ (t₁ + 16 )     ⇒  V * (t₁ + 16 ) = 4*d     ⇒ V*t₁ + 16*V = 384

So we a 2 equation system with two uknown variables

1.5*V = 96/t₁      (1)

V*t₁  + 16*V = 384     (2)

We solve  from equation    (1)      t₁  = 64/V

And by substitution   in equation (2)

V * (64/V) + 16* V = 384

64  + 16 *V  = 384         ⇒   16*V = 320      ⇒  V= 320/16

V = 20 miles /sec

6 0
3 years ago
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