The perimeter of a rectangle is found by multiplying the length by 2 and the width by 2 and adding them together.
P = 2L + 2W
Filling in the information given we can find the width:
16.8 = 2(3.6) + 2W
16.8 = 7.2 + 2W
2w = 16.8 - 7.2
2w = 9.6
w = 9.6 / 2
w = 4.8 in.
Answer:
a= 200
b = 210
Step-by-step explanation:
My assumption is, we have to find the length of sides of rectangle
Given
perimeter = 2a + 2b = 820 ft (i) (here a is smaller side and b is larger side)
area = a*b = 42,000 ft^2 (ii)
from eq (1)
2a + 2b = 820
=> 2(a+b) = 820
=> a+b = 820/2
=> a + b = 410
=> a = 410-b (iii)
putting the value of a in eq(ii), we get
(410-b) *b = 42,000
410b - b^2 = 42,000
0 = b^2 - 410b + 42000
b^2 - 410b + 42000 = 0
b^2- 200b- 210b + 42000 = 0
b(b-200)-210(b-200) = 0
(b-200)(b-210) = 0
or
b= 210 and b = 200
if b is larger side than b =210
By putting value of b in eq(iii),
a = 410 -210 = 200
What pair of fractions? I will be able to help i just need to know what fractions to use :)
To subtract fractions, we need a common denominator.
-
the common denominator will be (y-2)(y+3)
The answer above will be the simplified form.
Answer:
x<-3
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
