Which polynomial is equal to (-3x^2 + 2x - 3) subtracted from (x^3 - x^2 + 3x)?
<h3><u><em>
Answer:</em></u></h3>
The polynomial equal to (-3x^2 + 2x - 3) subtracted from (x^3 - x^2 + 3x) is 
<h3><u><em>Solution:</em></u></h3>
Given that two polynomials are: 
and 
We have to find the result when is subtracted from
In basic arithmetic operations,
when "a" is subtracted from "b" , the result is b - a
Similarly,
When is subtracted from , the result is:
Let us solve the above expression
<em><u>There are two simple rules to remember: </u></em>
- When you multiply a negative number by a positive number then the product is always negative.
- When you multiply two negative numbers or two positive numbers then the product is always positive.
So the above expression becomes:
Removing the brackets we get,
Combining the like terms,
Thus the resulting polynomial is found
Answer:
<em>A is correct answer</em>
Step-by-step explanation:
Thanks
Don't forget to tell the name of your country.
Answer:
Step-by-step explanation:
Sec B
1) 5p⁻³ = 8*5⁻²
p⁻³ = 2³*5⁻²/5
p⁻³ =2³*5⁻³ { 1/a^m = a^-m}
p⁻³ = 5⁻³ /2⁻³ {a^m = 1/a^-m}
p⁻³ = (5/2)⁻³
p= 5/2
2) 4x² = 81
x² = 81/4
x² = 9² /2²
x² =(9/2)²
x = 9/2
3) 9^x/3 =81
9^x/3 = 9^2
Comparing the powers, x/3 = 2
x = 2*3 =6
x = 6
Answer: Sequence B is more probable than A.
Step-by-step explanation:
This two sequences are not equally probable. Sequence B is more probable than A due to the equal chances of getting head (H) and a tail (T). The probability of getting a head is equal to the probability of getting a tail which is 4/8 i.e 0.5
The sequence A is less probable because the head(H) occur more than tail (T). The probability of head occurring is almost a sure event i.e 1 which is not feasible.
Answer: The required solution of the given IVP is
Step-by-step explanation: We are given to find the solution of the following initial value problem :
Let 
be an auxiliary solution of the given differential equation.
Then, we have
Substituting these values in the given differential equation, we have
![m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.](https://tex.z-dn.net/?f=m%5E2e%5E%7Bmx%7D-e%5E%7Bmx%7D%3D0%5C%5C%5C%5C%5CRightarrow%20%28m%5E2-1%29e%5E%7Bmx%7D%3D0%5C%5C%5C%5C%5CRightarrow%20m%5E2-1%3D0~~~~~~~~~~~~~~~~~~~~~~~~~~%5B%5Ctextup%7Bsince%20%7De%5E%7Bmx%7D%5Cneq0%5D%5C%5C%5C%5C%5CRightarrow%20m%5E2%3D1%5C%5C%5C%5C%5CRightarrow%20m%3D%5Cpm1.)
So, the general solution of the given equation is
where A and B are constants.
This gives, after differentiating with respect to x that
The given conditions implies that
and
Adding equations (i) and (ii), we get
From equation (i), we get
Substituting the values of A and B in the general solution, we get
Thus, the required solution of the given IVP is
