3 years ago

24. Analyze Relationships There are three numbers a, b, and c, where a > b

Mathematics

1 answer:

mestny [16]3 years ago

6 0

Answer:

A-is farthest to the right on the number line

B-in the middle of the number line

C- farthest to the left on the number line

Step-by-explanation

If we have 3 random numbers we can conclude that a<c so we can say

A is farthest to the right

B in the middle

C: farthest to the left.

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AURORKA [14]

G(x) = 3x² - 5x + 7
g(-x) = -(3x² - 5x + 7)
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This equation cannot be solved because of a few reasons,

1. This equation didn't show that it equals to 0.
2. Even if it equals to zero, square root of a negative number cannot be solved.
(I will show you what I mean)

-3x² + 5x - 7
is the same as
3x² - 5x + 7
by shifting the equation,

for example,
1 - 3 = -2
shifting other side
2 = -1 + 3

using 3x² - 5x + 7 to solve,

$Solve\ using\ the\ formular\ \ \boxed{ x= { \frac{-b \pm \sqrt{b^2-4ac} }{2a} } }$
a = 3
b = -5
c = 7
$x= { \frac {-(-5) \pm \sqrt{ (-5)^2-4(3)(7) } }{2(3)} }$
$x= { \frac {5 \pm \sqrt{-59} }{6} }$

∴This equation cannot be solved.

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