Answer:
-85
Step-by-step explanation:
<em><u>1) (2 + 3)</u></em>
-7 + {12 - 3[50 - 4(5) ] }
<em><u>2) -7 + {12 - 3[50 - 20] }</u></em>
-7 + {12 - 3[30] }
<em><u>3) -7 + 12 - 90</u></em>
5 - 90
<u>Answer: -85</u>
9514 1404 393
Answer:
smaller triangle area = 73 1/3 ft^2
Step-by-step explanation:
The smaller triangle has a ratio of linear dimensions of 10/15 = 2/3 of that of the larger triangle. The area ratio is the square of this, so the area of the smaller triangle is ...
(165 ft^2)(2/3)^2 = (165 ft^2)(4/9) = 220/3 ft^2 = 73 1/3 ft^2
CL.1.142):
A):
x5 ==> 4 boxes = 3ft <==== x5
20 boxes = ? ft
20 boxes is 15 ft. high
B): x3 ===> 4 boxes = 3ft. <==== x3
? boxes = 9ft.
12 boxes will fit in one stack.
c): CL.143
Perimeter = 15 + 29 + 9 + 11 + 6 + 18 =====> 88m
A1 = b * h
(18)(15)
270m^2
A2 = b * h
(11)(9)
99
Total Area ======> 270 + 99 ======> 369m^2
CL.1-144
1/4 + 1/4 + 1/5 = 5/20 + 5/20 + 4/20 ====> 14/20
1/4 * 5/5 =====> 5/20
1/5 * 4/4 =====> 4/20
14/20 + ?/20 = 20/20
? = 6 Missing Section
6/20 ======> 3/10
CL-1.145
A): 40/100 = 4/10 ====> 2/5
0.4 ========> 40%
B): 1/6 ======> .00000
0.16 (Repeating 6) ======> 16.6%
C): 37.5/100 = 375/1000 =======> 3/8
0.375 =========> 37.5%
CL-1.146
ADD: 1/6 + 1/2 show all steps:
1/6 + 1/2
1/6 + 3/6
1 + 3 / 6
4/6 =======> 2/3 =======> Decimal: =======> 0.666667
Hope that helps!!!! : )
Answer:
5.44 cm³
Step-by-step explanation:
The volume of the hexagonal nut can be found by multiplying the area of the end face by the length of the nut. The end face area is the difference between the area of the hexagon and the area of the hole.
The area of a hexagon with side length s is given by ...
A = (3/2)√3·s²
For s=1 cm, the area is ...
A = (3/2)√3(1 cm)² = (3/2)√3 cm²
__
The area of a circle is given by ...
A = πr²
The radius of a circle with diameter 1 cm is 0.5 cm. Then the area of the hole is ...
A = π(0.5 cm)² = 0.25π cm²
__
The volume is the face area multiplied by the length, so is ...
V = Bh = ((3/2)√3 -0.25π)(3) . . . . . cm³
V = (9/2)√3 -0.75π cm³ ≈ 5.44 cm³
The volume of the metal is about 5.44 cm³.
