Answer:
<em>Any width less than 3 feet</em>
Step-by-step explanation:
<u>Inequalities</u>
The garden plot will have an area of less than 18 square feet. If L is the length of the garden plot and W is the width, the area is calculated by:
A = L.W
The first condition can be written as follows:
LW < 18
The length should be 3 feet longer than the width, thus:
L = W + 3
Substituting in the inequality:
(W + 3)W < 18
Operating and rearranging:

Factoring:
(W-3)(W+6)<0
Since W must be positive, the only restriction comes from:
W - 3 < 0
Or, equivalently:
W < 3
Since:
L = W + 3
W = L - 3
This means:
L - 3 < 3
L < 6
The width should be less than 3 feet and therefore the length will be less than 6 feet.
If the measures are whole numbers, the possible dimensions of the garden plot are:
W = 1 ft, L = 4 ft
W = 2 ft, L = 5 ft
Another solution would be (for non-integer numbers):
W = 2.5 ft, L = 5.5 ft
There are infinitely many possible combinations for W and L as real numbers.
Answer:
-12
Step-by-step explanation:
Let the number be A
Given if you divide the sum of six and the number A by 3 , the result is 4 more than 1/4 of A
That’s
6+A/3 = 4+1/4 of A
6+A/3 = 4+1/4 x A
6+A/3 = 4+A/4
Cross multiply
4(6 + A) = 3(4 + A)
Distribute
4 x 6 + 4 x A = 3 x 4 + 3 x A
24 + 4A = 12 + 3A
Subtract 24 from both sides to eliminate 24 on the left side
24 - 24 + 4A = 12 - 24 + 3A
4A = -12 + 3A
Subtract 3A from both sides so the unknown can be on one side
4A - 3A = -12 + 3A - 3A
A = -12
Check
6+(-12)/3 = 4 +(-12)/4
6 -12/3 = 4 -12/4
-6/3 = -8/4
-2 = -2
Answer:
x=2
Step-by-step explanation:
First multiply both sides by 2:
6x-10=4-x
Move the variable to the left-hand side and change its sign:
6x-10+x=4
Move the constant to the right-hand side and change its sign:
6x+x=4+10
Collect like terms:
7x=14
Divide both sides of the equation by 7:
x=2
Answer:
14.1
Step-by-step explanation:

The statement that: pairs of corresponding points lie on parallel lines in a reflection, is false.
<h3>What are reflections?</h3>
When a point is reflected, then the point is flipped across a point or line of reflection
When a point is reflected, the following highlights are possible
- The corresponding points can line on the same line
- The corresponding points can line on parallel lines
Using the above highlights, we can conclude that the statement is false.
This is so because, corresponding points are not always on parallel lines
Read more about reflection at:
brainly.com/question/23970016