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zepelin [54]
3 years ago
8

14. What is the rate if the distance traveled is 360 miles for 6 hours?

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
8 0

Answer:

60

Step-by-step explanation:

360/6=60

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The table below shows the cost of riding in a taxi cab. What is the rate of change?
hjlf
Choose any 2 points from the table:

<span>*10----------------------$25
*15----------------------$35
*20----------------------$45
*25----------------------$55

and find the slope of the line.  Supposing we focus on

</span>*15----------------------$35
*20----------------------$45

then:
                     $45-$35         $10
slope = m = ------------- = ---------- = $2/mile
                       20-15              5
3 0
3 years ago
A rectangular box is 6 inches wide 10 inches long and 2 inches tall how much wrapping paper is needed to cover the box exactly
stepladder [879]

Answer:

184 in²

Step-by-step explanation:

Given :

Width, w = 6 inches

Length, l = 10 inches

Height, h = 2 inches

To obtain how much wrapping paper is needed ; we take the surface area of the box

Surface area = 2(lw + lh + wh)

Surface area = 2((6*10) + (6*2) + (10*2))

Surface area = 2(60 + 12 + 20)

Surface area = 2(92)

Surface area = 184 in²

The amount of wrapping paper needed = 184 in²

7 0
3 years ago
Solve<br>4(2x - 3) = 6x + 2​
Aleks [24]
X=7 hope it helps!!!!
8 0
2 years ago
Read 2 more answers
If ABCD is a parallelogram, what can we say about the diagonals BD and AC?
lidiya [134]
B. The diagonals bisect each other.
4 0
3 years ago
Read 2 more answers
Given: ABCD is a ∥-gram, BF ⊥ CD , BE ⊥ AD, Prove: △ABE∼△CBF
drek231 [11]

Answer:

Hence proved △ABE∼△CBF.

Step-by-step explanation:

Given,

ABCD is a parallelogram.

BF ⊥ CD    and

BE ⊥ AD

To Prove : △ABE∼△CBF

We have drawn the diagram for your reference.

Proof:

Since ABCD is a parallelogram,

So according to the property of parallelogram opposite angles are equal in measure.

\therefore m\angle A = m\angle B ⇒1

And given that BF ⊥ CD and BE ⊥ AD.

So we can say that;

m\angle F=m\angle E=90\° ⇒2

Now In △ABE and △CBF

∠A = ∠C   (from 1)

∠E = ∠F    (from 2)

So by A.A. similarity postulate;

△ABE∼△CBF

7 0
3 years ago
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