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3 years ago

Empirical formula of 25.13g sulfur and 49.87g copper

Chemistry

1 answer:

antiseptic1488 [7]3 years ago

7 0

Copper + sulfur create copper sulfide.

It's a lengthy process to find the empirical formula:

Sulfur:

$25.13g * \frac{1 mol}{32.065 g} = 0.78 mol$

Copper:

$49.87 * \frac{1 mol}{63.546 g} = 0.78mol$

S:Cu => $\frac{0.78}{0.78} :\frac{0.78}{0.78}$ => $(1:1) * 1$ => $1:1$

The empirical formula would just be $CuS$

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What is an everyday example of covalent bonds and ionic bonds

ludmilkaskok [199]

Answer:

1. CARBON DIOXIDE- it is a covalent compound, which is used in soft/cold drinks and some other fluids as well , and use it in daily life.

2. HYDROGEN MONOXIDE- it is the normal or original or pure water which we drink everyday in our daily life and it is very important for our survival

Explanation:

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3 years ago

Select the correct answer.

Step2247 [10]

Answer:

Vanadium(V) oxide is the inorganic compound with the formula V2O5. Commonly known as vanadium pentoxide,

Explanation:

then it is answer D

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3 years ago

In acidic solution, the sulfate ion can be used to react with a number of metal ions. One such reaction is SO42−(aq) Sn2 (aq)→H2

Sav [38]

Answer:

SO₄²⁻(aq) +Sn²⁺(aq) +4H⁺ → H₂SO₃(aq) + Sn⁴⁺(aq) + H₂O

Explanation:

At first calculate the oxidation state of that element which undergoes oxidation as well as reduction.

for SO₄²⁻ the oxidation state of sulphur is +6 and H₂SO₃ the oxidation state of sulphur is +4

So balance equation is

(Reduction) SO₄²⁻ + 4H⁺+ 2e⁻ → H₂SO₃ + H₂O.........................................(1)

(oxidation) Sn²⁺ → Sn⁴⁺ + 2e⁻ .............................................................(2)

Adding equation 1 & 2

we get

SO₄²⁻(aq) +Sn²⁺(aq) +4H⁺ → H₂SO₃(aq) + Sn⁴⁺(aq) + H₂O

6 0

4 years ago

Which salt has a pH < 7? KBr HCOOK CaSO4 NH4NO3

Eva8 [605]

If a salt has a pH less than 7, then it is an acid. All acids start with a H in there formula. The only compound that starts with an H from the listed options is HCOOK.

So the salt HCOOK has a pH<7

5 0

4 years ago

Read 2 more answers

(a) The mass density of a gaseous compound was found to be 1.23 kg m^−3 at 330 K and 20 kPa. What is the molar mass of the compo

Luden [163]

Answer:

The molar mass of the compound is:- 168.82 g/mol

The molar mass of the gas is:- 16.38 g/mol

Explanation:

(a)

Using ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Also,

Moles = mass (m) / Molar mass (M)

Density (d) = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

$PM=dRt$

Given that:-

Pressure = 20 kPa = 20000 Pa

The expression for the conversion of pressure in Pascal to pressure in atm is shown below:

P (Pa) = $\frac {1}{101325}$ P (atm)

20000 Pa = $\frac {20000}{101325}$ atm

Pressure = 0.1974 atm

Temperature = 330 K

d = 1.23 kg/m³ = 1.23 g/L

Molar mass = ?

Applying the equation as:

0.1974 atm × M = 1.23 g/L × 0.0821 L.atm/K.mol × 330 K

⇒M = 168.82 g/mol

The molar mass of the compound is:- 168.82 g/mol

(b)

Given that:

Pressure = 152 Torr

Temperature = 298 K

Volume = 250 cm³ = 0.25 L

Using ideal gas equation as:

$PV=nRT$

R = $62.3637\text{torr}mol^{-1}K^{-1}$

Applying the equation as:

152 Torr × 0.25 L = n × 62.3637 L.torr/K.mol × 298 K

⇒n = 0.002045 moles

Given that :

Mass of the gas = 33.5 mg = 0.0335 g

Molar mass = ?

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$0.002045\ moles
= \frac{0.0335\ g}{Molar\ mass}$

The molar mass of the gas is:- 16.38 g/mol

5 0

3 years ago