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erma4kov [3.2K]
3 years ago
13

In acidic solution, the sulfate ion can be used to react with a number of metal ions. One such reaction is SO42−(aq) Sn2 (aq)→H2

SO3(aq) Sn4 (aq) Since this reaction takes place in acidic solution, H2O(l) and H (aq) will be involved in the reaction. Places for these species are indicated by the blanks in the following restatement of the equation: SO42−(aq) Sn2 (aq) –––→H2SO3(aq) Sn4 (aq) –––
Chemistry
1 answer:
Sav [38]3 years ago
6 0

Answer:

SO₄²⁻(aq) +Sn²⁺(aq) +4H⁺ → H₂SO₃(aq) + Sn⁴⁺(aq) + H₂O

Explanation:

At first calculate the oxidation state of that element which undergoes oxidation as well as reduction.

for SO₄²⁻ the oxidation state of sulphur is +6 and H₂SO₃ the oxidation state of sulphur is +4

So balance equation is

(Reduction)      SO₄²⁻ + 4H⁺+ 2e⁻ → H₂SO₃ + H₂O.........................................(1)

(oxidation)        Sn²⁺ → Sn⁴⁺ + 2e⁻ .............................................................(2)

Adding equation 1 & 2

we get

SO₄²⁻(aq) +Sn²⁺(aq) +4H⁺ → H₂SO₃(aq) + Sn⁴⁺(aq) + H₂O

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A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 liters and a temperature of 20 degrees celsius,
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0.714 liter.

Explanation:

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What will be the volume of the balloon after he heats it to a temperature of 250 degrees Celsius ?

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Let the final volume of balloon is V_{2}

And a given, final temperature of balloon, T_{2} is 250°C = (273 + 250)K

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V_{2} = KT_{2}

    =K\times523\ (equation 2)

Dividing equation 1 and 2,

 \frac{4\times10^{-4}}{V_{2} } =\frac{K\times293}{K\times523}

K cancelled by K.

By cross multiplication:

293V_{2} =4\times10^{-4} \times523\\V_{2} =\frac{ 4\times10^{-4} \times523\\}{293} \\          = \frac{2092\times10^{-4}}{293} \\          =7.14\times10^{-4}m^{3}

Now convert it into liter with the help of calculation done above.

7.14\times10^{-4} \times1000\\7.14\times10^{-4} \times10^{3} \\0.714\ liter

Therefore, the volume of the balloon be after he heats it to a temperature of 250 degrees Celsius is 0.714 liter.

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